OCR MEI Paper 2 Specimen — Question 12 6 marks

Exam BoardOCR MEI
ModulePaper 2 (Paper 2)
SessionSpecimen
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicImplicit equations and differentiation
TypeFind stationary points
DifficultyStandard +0.8 This question requires implicit differentiation (a C4/FP1 topic), algebraic manipulation to find dy/dx, and then analysis of stationary points requiring setting dy/dx = 0 and proving a general result. Part (b) requires insight that numerator = 0 implies x = 0. More demanding than standard implicit differentiation exercises due to the proof element and multi-step reasoning.
Spec1.07s Parametric and implicit differentiation

Fig. 12 shows the curve \(2x^3 + y^3 = 5y\). \includegraphics{figure_12}
  1. Find the gradient of the curve \(2x^3 + y^3 = 5y\) at the point \((1,2)\), giving your answer in exact form. [4]
  2. Show that all the stationary points of the curve lie on the \(y\)-axis. [2]

Question 12:
AnswerMarks Guidance
12(a) e
p
dy dy (cid:170) dy 6x2 (cid:186)
6x2 (cid:14)3y2 (cid:32)5 (cid:171)(cid:159) (cid:32) (cid:187)
dx dx dx 5(cid:16)3y2
(cid:172) (cid:188)
S
dy dy
when x = 1, y = 2, 6 (cid:14) 12 (cid:32) 5
dx dx
dy 6
(cid:159) (cid:32) (cid:16)
AnswerMarks
dx 7M1
A1
M1
A1
AnswerMarks
[4]1.1a
1.1
1.1
AnswerMarks
2.1implicit differentation
correct
substituting x = 1, y = 2
cao
AnswerMarks Guidance
12(b) dy
(cid:32)0 so 6x2 (cid:32)0
dx
AnswerMarks
x(cid:32)0 so all stationary points lie on y-axisB1
E1
AnswerMarks
[2]1.2
2.1dy
Substitute (cid:32)0 into their
dx
differentiated expression
Completion of argument
Question 12:
12 | (a) | e
p
dy dy (cid:170) dy 6x2 (cid:186)
6x2 (cid:14)3y2 (cid:32)5 (cid:171)(cid:159) (cid:32) (cid:187)
dx dx dx 5(cid:16)3y2
(cid:172) (cid:188)
S
dy dy
when x = 1, y = 2, 6 (cid:14) 12 (cid:32) 5
dx dx
dy 6
(cid:159) (cid:32) (cid:16)
dx 7 | M1
A1
M1
A1
[4] | 1.1a
1.1
1.1
2.1 | implicit differentation
correct
substituting x = 1, y = 2
cao
12 | (b) | dy
(cid:32)0 so 6x2 (cid:32)0
dx
x(cid:32)0 so all stationary points lie on y-axis | B1
E1
[2] | 1.2
2.1 | dy
Substitute (cid:32)0 into their
dx
differentiated expression
Completion of argument
Fig. 12 shows the curve $2x^3 + y^3 = 5y$.

\includegraphics{figure_12}

\begin{enumerate}[label=(\alph*)]
\item Find the gradient of the curve $2x^3 + y^3 = 5y$ at the point $(1,2)$, giving your answer in exact form. [4]
\item Show that all the stationary points of the curve lie on the $y$-axis. [2]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Paper 2  Q12 [6]}}