OCR MEI AS Paper 2 2018 June — Question 5 3 marks

Exam BoardOCR MEI
ModuleAS Paper 2 (AS Paper 2)
Year2018
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscriminant and conditions for roots
TypeFind range for no real roots
DifficultyModerate -0.8 This is a straightforward discriminant question requiring students to recall that b²-4ac < 0 for no real roots, then solve the simple inequality 64-8a < 0 to get a > 8. It's slightly easier than average because it's a direct application of a standard technique with minimal algebraic manipulation.
Spec1.02d Quadratic functions: graphs and discriminant conditions

Find the set of values of \(a\) for which the equation $$ax^2 + 8x + 2 = 0$$ has no real roots. [3]

Question 5:
AnswerMarks
5Use of discriminant
82 ‒ 4×a × 2 < 0
AnswerMarks
a > 8M1
A1
A1
AnswerMarks
[3]3.1a
1.1
AnswerMarks
1.1Accept = or any inequality
Accept 8 < aValues must be substituted
Question 5:
5 | Use of discriminant
82 ‒ 4×a × 2 < 0
a > 8 | M1
A1
A1
[3] | 3.1a
1.1
1.1 | Accept = or any inequality
Accept 8 < a | Values must be substituted
Find the set of values of $a$ for which the equation
$$ax^2 + 8x + 2 = 0$$
has no real roots. [3]

\hfill \mbox{\textit{OCR MEI AS Paper 2 2018 Q5 [3]}}