OCR PURE — Question 7 7 marks

Exam BoardOCR
ModulePURE
Marks7
PaperDownload PDF ↗
TopicVectors Introduction & 2D
TypeGeometric properties using vectors
DifficultyModerate -0.8 This is a straightforward vector geometry question requiring basic vector addition and the midpoint formula. Part (i) involves routine manipulation (AC = c - a, OP = ½(a + c)), while part (ii) asks for a standard proof that diagonals bisect each other—a well-known result with a direct approach. The 7-mark allocation suggests multiple small steps rather than conceptual difficulty, making this easier than average for A-level.
Spec1.10a Vectors in 2D: i,j notation and column vectors1.10d Vector operations: addition and scalar multiplication1.10e Position vectors: and displacement1.10g Problem solving with vectors: in geometry

\(OABC\) is a parallelogram with \(\overrightarrow{OA} = \mathbf{a}\) and \(\overrightarrow{OC} = \mathbf{c}\). \(P\) is the midpoint of \(AC\). \includegraphics{figure_7}
  1. Find the following in terms of \(\mathbf{a}\) and \(\mathbf{c}\), simplifying your answers.
    1. \(\overrightarrow{AC}\) [1]
    2. \(\overrightarrow{OP}\) [2]
  2. Hence prove that the diagonals of a parallelogram bisect one another. [4]

$OABC$ is a parallelogram with $\overrightarrow{OA} = \mathbf{a}$ and $\overrightarrow{OC} = \mathbf{c}$. $P$ is the midpoint of $AC$.

\includegraphics{figure_7}

\begin{enumerate}[label=(\roman*)]
\item Find the following in terms of $\mathbf{a}$ and $\mathbf{c}$, simplifying your answers.

\begin{enumerate}[label=(\alph*)]
\item $\overrightarrow{AC}$ [1]

\item $\overrightarrow{OP}$ [2]
\end{enumerate}

\item Hence prove that the diagonals of a parallelogram bisect one another. [4]
\end{enumerate}

\hfill \mbox{\textit{OCR PURE  Q7 [7]}}