Edexcel AS Paper 1 — Question 12 5 marks

Exam BoardEdexcel
ModuleAS Paper 1 (AS Paper 1)
Marks5
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TopicStandard trigonometric equations
TypeProduct of trig functions
DifficultyStandard +0.3 Part (a) requires recognizing that cos θ is bounded between -1 and 1, making both factors impossible to equal zero—a straightforward conceptual check. Part (b) involves factorizing using sin y = tan y · cos y, leading to a simple quadratic in cos y, which is standard AS-level trigonometry. The question tests understanding of trigonometric bounds and basic algebraic manipulation rather than requiring novel problem-solving.
Spec1.05a Sine, cosine, tangent: definitions for all arguments1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals

  1. Explain mathematically why there are no values of \(\theta\) that satisfy the equation $$(3\cos\theta - 4)(2\cos\theta + 5) = 0$$ [2]
  2. Giving your solutions to one decimal place, where appropriate, solve the equation $$3\sin y + 2\tan y = 0 \quad \text{for } 0 \leq y \leq \pi$$ (Solutions based entirely on graphical or numerical methods are not acceptable.) [3]

Part a:
AnswerMarks Guidance
\(\cos\theta = \frac{4}{3}\) and \(\cos\theta = -\frac{5}{2}\); since \(\cos\theta\) takes values between -1 and 1, there does not exist such a \(\theta\) to satisfy these equationsB1, B1 Attempts to find the values of \(\cos\theta\); Requires a correct statement and conclusion
Part b:
AnswerMarks Guidance
\(y = 0, \pi\); \(\cos y = -\frac{2}{3}\) gives no solutions; Solutions: \(y = 0, \pi\)M1, M1, A1 Uses a trigonometric substitution in the given equation; Correct work leading to 2 factors; All solutions correct
### Part a:
$\cos\theta = \frac{4}{3}$ and $\cos\theta = -\frac{5}{2}$; since $\cos\theta$ takes values between -1 and 1, there does not exist such a $\theta$ to satisfy these equations | B1, B1 | Attempts to find the values of $\cos\theta$; Requires a correct statement and conclusion

### Part b:
$y = 0, \pi$; $\cos y = -\frac{2}{3}$ gives no solutions; Solutions: $y = 0, \pi$ | M1, M1, A1 | Uses a trigonometric substitution in the given equation; Correct work leading to 2 factors; All solutions correct
\begin{enumerate}[label=(\alph*)]
\item Explain mathematically why there are no values of $\theta$ that satisfy the equation
$$(3\cos\theta - 4)(2\cos\theta + 5) = 0$$ [2]
\item Giving your solutions to one decimal place, where appropriate, solve the equation
$$3\sin y + 2\tan y = 0 \quad \text{for } 0 \leq y \leq \pi$$
(Solutions based entirely on graphical or numerical methods are not acceptable.) [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel AS Paper 1  Q12 [5]}}