Edexcel AS Paper 1 — Question 5 4 marks

Exam BoardEdexcel
ModuleAS Paper 1 (AS Paper 1)
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLaws of Logarithms
TypeIdentify errors in student work
DifficultyModerate -0.3 This is a slightly easier than average A-level question. Part (a) requires spotting a common logarithm error (incorrect application of log subtraction rule), which is straightforward pattern recognition. Part (b) involves standard logarithm manipulation, solving a quadratic, and checking validity of solutions—all routine AS-level techniques with no novel problem-solving required.
Spec1.06c Logarithm definition: log_a(x) as inverse of a^x1.06f Laws of logarithms: addition, subtraction, power rules

A student is asked to solve the equation $$\log_3 x - \log_3 \sqrt{x - 2} = 1$$ The student's attempt is shown $$\log_3 x - \log_3 \sqrt{x - 2} = 1$$ $$x - \sqrt{x - 2} = 3^1$$ $$x - 3 = \sqrt{x - 2}$$ $$(x - 3)^2 = x - 2$$ $$x^2 - 7x + 11 = 0$$ $$x = \frac{7 + \sqrt{5}}{2} \text{ or } x = \frac{7 - \sqrt{5}}{2}$$
  1. Identify the error made by this student, giving a brief explanation. [1]
  2. Write out the correct solution. [3]

Part a:
AnswerMarks Guidance
The student goes wrong in line 2, where the subtraction should be a division as \(\log x - \log y = \log\frac{x}{y}\)B1 (1 mark)
Part b:
AnswerMarks Guidance
\(x = 6, x = 3\)M1, M1, A1 Using the subtraction law and power law correctly; Student obtains a quadratic and correctly factorises their quadratic; Both values of \(x\) are correct
### Part a:
The student goes wrong in line 2, where the subtraction should be a division as $\log x - \log y = \log\frac{x}{y}$ | B1 | (1 mark)

### Part b:
$x = 6, x = 3$ | M1, M1, A1 | Using the subtraction law and power law correctly; Student obtains a quadratic and correctly factorises their quadratic; Both values of $x$ are correct
A student is asked to solve the equation
$$\log_3 x - \log_3 \sqrt{x - 2} = 1$$

The student's attempt is shown
$$\log_3 x - \log_3 \sqrt{x - 2} = 1$$
$$x - \sqrt{x - 2} = 3^1$$
$$x - 3 = \sqrt{x - 2}$$
$$(x - 3)^2 = x - 2$$
$$x^2 - 7x + 11 = 0$$
$$x = \frac{7 + \sqrt{5}}{2} \text{ or } x = \frac{7 - \sqrt{5}}{2}$$

\begin{enumerate}[label=(\alph*)]
\item Identify the error made by this student, giving a brief explanation. [1]
\item Write out the correct solution. [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel AS Paper 1  Q5 [4]}}