| Exam Board | AQA |
|---|---|
| Module | Paper 2 (Paper 2) |
| Year | 2019 |
| Session | June |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Vectors Introduction & 2D |
| Type | Geometric properties using vectors |
| Difficulty | Moderate -0.3 This is a straightforward vectors question requiring standard techniques: computing direction vectors to show parallel sides for part (a), and calculating distance then speed for part (b). While the numbers are large, the conceptual demands are routine—no novel insight or complex multi-step reasoning is needed, making it slightly easier than average. |
| Spec | 1.10a Vectors in 2D: i,j notation and column vectors1.10d Vector operations: addition and scalar multiplication1.10f Distance between points: using position vectors |
| Answer | Marks |
|---|---|
| 15(a) | Finds or or or |
| Answer | Marks | Guidance |
|---|---|---|
| ratios here | 3.1a | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| labelled as gradients or vectors | 1.1b | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| M1 A0 A0 E1 R0 | 1.1b | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| marks | 3.2a | E1 |
| Answer | Marks | Guidance |
|---|---|---|
| CSO | 2.1 | R1 |
| Answer | Marks |
|---|---|
| 15(b) | Uses velocity/displacement/time |
| Answer | Marks | Guidance |
|---|---|---|
| /distance from part 15(a) by 50 | 3.1b | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| 𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆 = | 𝒗𝒗 | = �2.6 +16.8 |
| Answer | Marks | Guidance |
|---|---|---|
| 𝐴𝐴����𝐶𝐶�⃗ | 1.1a | M1 |
| Obtains 17 | 1.1a | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| units | 3.2a | A1 |
| Total | 9 | |
| Q | Marking Instructions | AO |
Question 15:
--- 15(a) ---
15(a) | Finds or or or
correctly
Condo𝐴𝐴�� ��𝐴𝐴� ⃗ d𝐶𝐶�� � �𝐶𝐶� ⃗ ctio𝐴𝐴� ���𝐶𝐶� ⃗ erro𝐶𝐶� � �� i𝐴𝐴� ⃗
n e a i r e n r n the
label
OE
or −130 −180
𝐴𝐴����𝐶𝐶�⃗ = � � �𝐶𝐶���𝐴𝐴�⃗ = � �
Finds g−ra8d4i0ent of or 750 or or
correctly
𝐴𝐴𝐴𝐴 9 𝐶𝐶𝐶𝐶 𝐴𝐴𝐶𝐶
𝐶𝐶G𝐴𝐴radient = = OE
31
𝐴𝐴𝐴𝐴 𝐶𝐶8𝐶𝐶4
Gradient = OE
13
𝐴𝐴𝐶𝐶 25
Gradient = − OE
6
𝐶𝐶𝐴𝐴 31 13 6
Accept ratios , ,− OE
9 84 25
Ignore any incorrect labelling of
ratios here | 3.1a | M1 | −620 930
𝐴𝐴����𝐴𝐴�⃗ = � � 𝐶𝐶����𝐶𝐶�⃗ = � �
−180 270
�𝐶𝐶���𝐶𝐶�⃗ = −1.5 ×�𝐴𝐴���𝐴𝐴�⃗
Thus and are parallel but
not equal in length
𝐴𝐴𝐴𝐴 𝐶𝐶𝐶𝐶
is a trapezium but not a
parallelogram
𝐴𝐴 𝐴𝐴𝐶𝐶𝐶𝐶
Finds and correctly
OE
𝐴𝐴����𝐴𝐴�⃗ 𝐶𝐶����𝐶𝐶�⃗
or
Finds gradients of and
correctly
or 𝐴𝐴𝐴𝐴 𝐶𝐶𝐶𝐶
Finds a corresponding pair of ratios
correctly – Do not award if
reciprocals of gradients are
labelled as gradients or vectors | 1.1b | A1
Shows/states OE
or
𝐶𝐶����𝐶𝐶�⃗ = ±1.5 ×𝐴𝐴����𝐴𝐴�⃗
Shows/states that
or
�𝐴𝐴���𝐶𝐶�⃗ ≠ 𝑘𝑘×�𝐶𝐶���𝐴𝐴�⃗
Finds and correctly
or
g𝐴𝐴���� r𝐶𝐶�⃗ �𝐶𝐶s ��� 𝐴𝐴� ⃗
Finds adient o f and
correctly
or 𝐴𝐴𝐶𝐶 𝐶𝐶𝐴𝐴
Finds a second corresponding pair
of ratios correctly– Do not award if
reciprocals of gradients are
labelled as gradients or vectors
If incorrect labelling used for ratios
then maximum mark is
M1 A0 A0 E1 R0 | 1.1b | A1
Deduces that and are
parallel - implied by reference to
gradients𝐴𝐴��� �𝐴𝐴�⃗ 𝐶𝐶����𝐶𝐶�⃗
equal
or
Deduces correctly that and
are not parallel
�𝐴𝐴�� �𝐶𝐶 �⃗ �𝐶𝐶h ���𝐴𝐴e �⃗
NB E1 is Independent o f any ot r
marks | 3.2a | E1
Completes rigorous proof by
deducing correctly that the scalar
multiple of OE means the
parallel sides are not equal in
length ±1.5
or
Completes rigorous proof by
deducing correctly that and
are parallel giving justification and
𝐴𝐴����𝐴𝐴�⃗ �𝐶𝐶���𝐶𝐶�⃗
that and are not parallel
giving justification
�𝐴𝐴���𝐶𝐶�⃗ �𝐶𝐶���𝐴𝐴�⃗
Must include a statement that
is not a parallelogram at
some point
𝐴𝐴 𝐴𝐴𝐶𝐶𝐶𝐶
NB R1 can be awarded even if E1
was not awarded
CSO | 2.1 | R1
--- 15(b) ---
15(b) | Uses velocity/displacement/time
relationship
Evidenced by dividing any vector
/distance from part 15(a) by 50 | 3.1b | M1 | 1 −130
𝒗𝒗= ×� �
50 −840
− 2.6
𝒗𝒗 = � �
−16.8
2 2
𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆 = |𝒗𝒗|= �2.6 +16.8
m s-1
𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆 = 17
Finds the magnitude of their
or v
𝐴𝐴����𝐶𝐶�⃗ | 1.1a | M1
Obtains 17 | 1.1a | A1
States correct speed with correct
units | 3.2a | A1
Total | 9
Q | Marking Instructions | AO | Marks | Typical Solution
Four buoys on the surface of a large, calm lake are located at $A$, $B$, $C$ and $D$ with position vectors given by
$$\overrightarrow{OA} = \begin{bmatrix} 410 \\ 710 \end{bmatrix}, \overrightarrow{OB} = \begin{bmatrix} -210 \\ 530 \end{bmatrix}, \overrightarrow{OC} = \begin{bmatrix} -340 \\ -310 \end{bmatrix} \text{ and } \overrightarrow{OD} = \begin{bmatrix} 590 \\ -40 \end{bmatrix}$$
All values are in metres.
\begin{enumerate}[label=(\alph*)]
\item Prove that the quadrilateral $ABCD$ is a trapezium but not a parallelogram. [5 marks]
\item A speed boat travels directly from $B$ to $C$ at a constant speed in 50 seconds.
Find the speed of the boat between $B$ and $C$. [4 marks]
\end{enumerate}
\hfill \mbox{\textit{AQA Paper 2 2019 Q15 [9]}}