AQA Paper 1 2024 June — Question 5 3 marks

Exam BoardAQA
ModulePaper 1 (Paper 1)
Year2024
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeBasic trig equation solving
DifficultyEasy -1.2 This is a straightforward trigonometric equation requiring only basic manipulation (recognizing sin²x = 1 means sin x = ±1) and recall of special angle values. The question is simpler than average A-level content as it involves no multi-step problem-solving, just direct application of fundamental trig knowledge to find two solutions in the given range.
Spec1.05o Trigonometric equations: solve in given intervals

Solve the equation $$\sin^2 x = 1$$ for \(0° < x < 360°\) [3 marks]

Question 5:
AnswerMarks
5Obtains s i n x =  1
Or
Obtains c o s x = 0
PI by a correct value for x
Condone radians and values
AnswerMarks Guidance
outside of range1.1a M1
x =90 ,270
Obtains 90 or 270
Or
 3
Obtains both and
AnswerMarks Guidance
2 21.1b A1
Obtains 90 and 270 and no
AnswerMarks Guidance
other values in the range.1.1b A1
Question 5 Total3
QMarking instructions AO
Question 5:
5 | Obtains s i n x =  1
Or
Obtains c o s x = 0
PI by a correct value for x
Condone radians and values
outside of range | 1.1a | M1 | sinx =1
x =90 ,270
Obtains 90 or 270
Or
 3
Obtains both and
2 2 | 1.1b | A1
Obtains 90 and 270 and no
other values in the range. | 1.1b | A1
Question 5 Total | 3
Q | Marking instructions | AO | Marks | Typical solution
Solve the equation
$$\sin^2 x = 1$$
for $0° < x < 360°$
[3 marks]

\hfill \mbox{\textit{AQA Paper 1 2024 Q5 [3]}}