AQA AS Paper 2 2024 June — Question 13 4 marks

Exam BoardAQA
ModuleAS Paper 2 (AS Paper 2)
Year2024
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPermutations & Arrangements
TypeLinear programming and optimization
DifficultyEasy -1.8 This is a straightforward stratified sampling question requiring only basic proportional calculations (multiply each year group by 50/720) and recall of a standard advantage. It involves minimal problem-solving and is purely procedural—significantly easier than average A-level questions.
Spec2.01c Sampling techniques: simple random, opportunity, etc2.01d Select/critique sampling: in context

The headteacher of a school wishes to collect the opinions of the students on a new timetable structure. To do this, a random sample of size 50, stratified by year group, will be selected. The school has a total of 720 students. The number of students in each of the year groups at this school is shown below.
Year group10111213
Number of students200240150130
  1. Find the number of students from each year group that should be selected in the stratified random sample. [3 marks]
  2. State one advantage of using a stratified random sample. [1 mark]

Question 13:

AnswerMarks Guidance
13(a)Uses at least one correct ratio
PI by at least one correct value3.1a M1
Year 10: × 50 = 13.9
720
2 4 0
Year 11: × 50 = 16.7
7 2 0
1 5 0
Year 12: × 50 = 10.4
7 2 0
1 3 0
Year 13: × 50 = 9.0
7 2 0
Y10: 14
Y11: 17
Y12: 10
Y13: 9
Obtains at least 2 correct values
Condone values given as
AnswerMarks Guidance
decimals1.1b A1
Obtains all 4 correct integer
values
Y10: 14
Y11: 17
Y12: 10
Y13: 9
AnswerMarks Guidance
CAO3.2a A1
Subtotal3
QMarking instructions AO

AnswerMarks
13(b)Gives any correct advantage of
a stratified sample
Accept:
Provides greater
precision/reliability
The sample is representative of
the population/each (year) group
AnswerMarks Guidance
Unbiased2.4 E1
in the sample
AnswerMarks Guidance
Subtotal1
Question 13 Total4
QMarking instructions AO
Question 13:
--- 13(a) ---
13(a) | Uses at least one correct ratio
PI by at least one correct value | 3.1a | M1 | 200
Year 10: × 50 = 13.9
720
2 4 0
Year 11: × 50 = 16.7
7 2 0
1 5 0
Year 12: × 50 = 10.4
7 2 0
1 3 0
Year 13: × 50 = 9.0
7 2 0
Y10: 14
Y11: 17
Y12: 10
Y13: 9
Obtains at least 2 correct values
Condone values given as
decimals | 1.1b | A1
Obtains all 4 correct integer
values
Y10: 14
Y11: 17
Y12: 10
Y13: 9
CAO | 3.2a | A1
Subtotal | 3
Q | Marking instructions | AO | Marks | Typical solution
--- 13(b) ---
13(b) | Gives any correct advantage of
a stratified sample
Accept:
Provides greater
precision/reliability
The sample is representative of
the population/each (year) group
Unbiased | 2.4 | E1 | Ensures each year group is included
in the sample
Subtotal | 1
Question 13 Total | 4
Q | Marking instructions | AO | Marks | Typical solution
The headteacher of a school wishes to collect the opinions of the students on a new timetable structure.

To do this, a random sample of size 50, stratified by year group, will be selected.

The school has a total of 720 students.

The number of students in each of the year groups at this school is shown below.

\begin{tabular}{|c|c|c|c|c|}
\hline
Year group & 10 & 11 & 12 & 13 \\
\hline
Number of students & 200 & 240 & 150 & 130 \\
\hline
\end{tabular}

\begin{enumerate}[label=(\alph*)]
\item Find the number of students from each year group that should be selected in the stratified random sample.
[3 marks]

\item State one advantage of using a stratified random sample.
[1 mark]
\end{enumerate}

\hfill \mbox{\textit{AQA AS Paper 2 2024 Q13 [4]}}