| Exam Board | AQA |
|---|---|
| Module | AS Paper 1 (AS Paper 1) |
| Year | 2023 |
| Session | June |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | SUVAT in 2D & Gravity |
| Type | Modelling assumptions and limitations |
| Difficulty | Moderate -0.3 This is a straightforward mechanics question requiring application of SUVAT equations with constant acceleration. Part (a) involves substituting known values into s = ut + ½at² and solving algebraically—routine for AS-level mechanics. Part (b) requires only qualitative reasoning about air resistance reducing acceleration. The question is slightly easier than average due to its standard structure and the 'show that' format which provides the target answer. |
| Spec | 3.02h Motion under gravity: vector form |
| Answer | Marks |
|---|---|
| 14(a) | Selects an appropriate equation |
| Answer | Marks | Guidance |
|---|---|---|
| PI by correct substitution | 1.1a | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| Substitutes s = 0.8h | 1.1a | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| to obtain given answer | 2.1 | R1 |
| Subtotal | 3 | |
| Q | Marking instructions | AO |
| Answer | Marks | Guidance |
|---|---|---|
| 14(b) | Explains that h will be less | 3.5a |
| Answer | Marks | Guidance |
|---|---|---|
| Subtotal | 1 | |
| Question 14 Total | 4 | |
| Q | Marking instructions | AO |
Question 14:
--- 14(a) ---
14(a) | Selects an appropriate equation
of constant acceleration.
and
states u = 0 , t = 4 and a = g
PI by correct substitution | 1.1a | M1 | 1
s = ut + at2
2
u = 0 , t = 4 and a = g
1
0.8h = g × 42
2
0.8h = 8g
h = 10g
Substitutes s = 0.8h | 1.1a | M1
Completes reasoned argument
to obtain given answer | 2.1 | R1
Subtotal | 3
Q | Marking instructions | AO | Marks | Typical solution
--- 14(b) ---
14(b) | Explains that h will be less | 3.5a | E1 | Air resistance will cause h to be
lower
Subtotal | 1
Question 14 Total | 4
Q | Marking instructions | AO | Marks | Typical solutionA ball, initially at rest, is dropped from a vertical height of $h$ metres above the Earth's surface.
After 4 seconds the ball's height above the Earth's surface is $0.2h$ metres.
\begin{enumerate}[label=(\alph*)]
\item Assuming air resistance can be ignored, show that
$$h = 10g$$
[3 marks]
\item Assuming air resistance cannot be ignored, explain the effect that this would have on the value of $h$ in part (a).
[1 mark]
\end{enumerate}
\hfill \mbox{\textit{AQA AS Paper 1 2023 Q14 [4]}}