AQA AS Paper 1 2019 June — Question 7 6 marks

Exam BoardAQA
ModuleAS Paper 1 (AS Paper 1)
Year2019
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProof
TypeAlgebraic inequality proof
DifficultyChallenging +1.2 This is a 6-mark AS-level proof requiring binomial expansion and algebraic manipulation. Students must expand both terms, observe that odd powers cancel, combine even powers, and recognize the resulting expression is non-negative. While it requires careful algebra and insight to see the cancellation pattern, it's a structured problem with a clear path once the expansion is done. The inequality proof is straightforward after simplification. Slightly above average difficulty for AS level due to the multi-step algebraic reasoning required.
Spec1.01a Proof: structure of mathematical proof and logical steps1.04a Binomial expansion: (a+b)^n for positive integer n

Given that \(y \in \mathbb{R}\), prove that $$(2 + 3y)^4 + (2 - 3y)^4 \geq 32$$ Fully justify your answer. [6 marks]

Question 7:
AnswerMarks Guidance
7Expands at least one bracket –
must reach a quartic3.1a M1
+ 4×2×(3y)3 + (3y)4
= 16 + 96y + 216y2 + 216y3 + 81y4
(2 – 3y)4 = 24 + 4×23×(–3y) +
6×22×(–3y)2 + 4×2×(–3y)3 + (–3y)4
= 16 - 96y + 216y2 - 216y3 + 81y4
(2 + 3y)4 + (2 – 3y)4
= 32 + 432y2 + 162y4
y2 ≥ 0 and y4 ≥ 0 for all y
(2 + 3y)4 + (2 – 3y)4 ≥ 32 for all y
Obtains at least one correct
expansion – not necessarily
AnswerMarks Guidance
simplified1.1b A1
Obtains two correct expansions –
AnswerMarks Guidance
not necessarily simplified1.1b A1
Combines their expansions to
obtain a sum containing only even
AnswerMarks Guidance
power terms.1.1a M1
Explains that y2 and y4 are always
positive or zero (for )
Or finds minimum value using
calculus and justifies𝑦𝑦 th∈isℝ as not just
AnswerMarks Guidance
a local minimum2.4 E1
Reaches correct conclusion. Sets
out a well-constructed mathematical
argument. R1 can be awarded if E1
AnswerMarks Guidance
not given.2.1 R1
Total6
QMarking Instructions AO
Question 7:
7 | Expands at least one bracket –
must reach a quartic | 3.1a | M1 | (2 + 3y)4 = 24 + 4×23×(3y) + 6×22×(3y)2
+ 4×2×(3y)3 + (3y)4
= 16 + 96y + 216y2 + 216y3 + 81y4
(2 – 3y)4 = 24 + 4×23×(–3y) +
6×22×(–3y)2 + 4×2×(–3y)3 + (–3y)4
= 16 - 96y + 216y2 - 216y3 + 81y4
(2 + 3y)4 + (2 – 3y)4
= 32 + 432y2 + 162y4
y2 ≥ 0 and y4 ≥ 0 for all y
(2 + 3y)4 + (2 – 3y)4 ≥ 32 for all y
Obtains at least one correct
expansion – not necessarily
simplified | 1.1b | A1
Obtains two correct expansions –
not necessarily simplified | 1.1b | A1
Combines their expansions to
obtain a sum containing only even
power terms. | 1.1a | M1
Explains that y2 and y4 are always
positive or zero (for )
Or finds minimum value using
calculus and justifies𝑦𝑦 th∈isℝ as not just
a local minimum | 2.4 | E1
Reaches correct conclusion. Sets
out a well-constructed mathematical
argument. R1 can be awarded if E1
not given. | 2.1 | R1
Total | 6
Q | Marking Instructions | AO | Marks | Typical Solution
Given that $y \in \mathbb{R}$, prove that
$$(2 + 3y)^4 + (2 - 3y)^4 \geq 32$$

Fully justify your answer.
[6 marks]

\hfill \mbox{\textit{AQA AS Paper 1 2019 Q7 [6]}}