A small ball \(B\) moves in the plane of a fixed horizontal axis \(Ox\), which lies on horizontal ground, and a fixed vertically upwards axis \(Oy\). \(B\) is projected from \(O\) with a velocity whose components along \(Ox\) and \(Oy\) are \(U \mathrm{m s}^{-1}\) and \(V \mathrm{m s}^{-1}\), respectively. The units of \(x\) and \(y\) are metres.
\(B\) is modelled as a particle moving freely under gravity.
- Show that the path of \(B\) has equation \(2U^2 y = 2UVx - gx^2\). [3]
During its motion, \(B\) just clears a vertical wall of height \(\frac{1}{3}a\) m at a horizontal distance \(a\) m from \(O\). \(B\) strikes the ground at a horizontal distance \(3a\) m beyond the wall.
- Determine the angle of projection of \(B\). Give your answer in degrees correct to 3 significant figures. [5]
- Given that the speed of projection of \(B\) is \(54.6 \mathrm{m s}^{-1}\), determine the value of \(a\). [2]
- Hence find the maximum height of \(B\) above the ground during its motion. [3]
- State one refinement of the model, other than including air resistance, that would make it more realistic. [1]