OCR H240/03 2022 June — Question 13 14 marks

Exam BoardOCR
ModuleH240/03 (Pure Mathematics and Mechanics)
Year2022
SessionJune
Marks14
PaperDownload PDF ↗
TopicProjectiles
TypeProjectile clearing obstacle
DifficultyStandard +0.3 This is a standard projectile motion question requiring derivation of trajectory equation (routine), then solving simultaneous equations using two points on the path. Part (b) involves algebraic manipulation but follows a predictable method. Parts (c)-(d) are straightforward substitutions once the angle is found. The question is slightly easier than average due to its structured, step-by-step nature with clear signposting, though it requires careful algebra across multiple parts.
Spec1.05c Area of triangle: using 1/2 ab sin(C)3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model

A small ball \(B\) moves in the plane of a fixed horizontal axis \(Ox\), which lies on horizontal ground, and a fixed vertically upwards axis \(Oy\). \(B\) is projected from \(O\) with a velocity whose components along \(Ox\) and \(Oy\) are \(U \mathrm{m s}^{-1}\) and \(V \mathrm{m s}^{-1}\), respectively. The units of \(x\) and \(y\) are metres. \(B\) is modelled as a particle moving freely under gravity.
  1. Show that the path of \(B\) has equation \(2U^2 y = 2UVx - gx^2\). [3]
During its motion, \(B\) just clears a vertical wall of height \(\frac{1}{3}a\) m at a horizontal distance \(a\) m from \(O\). \(B\) strikes the ground at a horizontal distance \(3a\) m beyond the wall.
  1. Determine the angle of projection of \(B\). Give your answer in degrees correct to 3 significant figures. [5]
  2. Given that the speed of projection of \(B\) is \(54.6 \mathrm{m s}^{-1}\), determine the value of \(a\). [2]
  3. Hence find the maximum height of \(B\) above the ground during its motion. [3]
  4. State one refinement of the model, other than including air resistance, that would make it more realistic. [1]

A small ball $B$ moves in the plane of a fixed horizontal axis $Ox$, which lies on horizontal ground, and a fixed vertically upwards axis $Oy$. $B$ is projected from $O$ with a velocity whose components along $Ox$ and $Oy$ are $U \mathrm{m s}^{-1}$ and $V \mathrm{m s}^{-1}$, respectively. The units of $x$ and $y$ are metres.

$B$ is modelled as a particle moving freely under gravity.

\begin{enumerate}[label=(\alph*)]
\item Show that the path of $B$ has equation $2U^2 y = 2UVx - gx^2$. [3]
\end{enumerate}

During its motion, $B$ just clears a vertical wall of height $\frac{1}{3}a$ m at a horizontal distance $a$ m from $O$. $B$ strikes the ground at a horizontal distance $3a$ m beyond the wall.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Determine the angle of projection of $B$. Give your answer in degrees correct to 3 significant figures. [5]
\item Given that the speed of projection of $B$ is $54.6 \mathrm{m s}^{-1}$, determine the value of $a$. [2]
\item Hence find the maximum height of $B$ above the ground during its motion. [3]
\item State one refinement of the model, other than including air resistance, that would make it more realistic. [1]
\end{enumerate}

\hfill \mbox{\textit{OCR H240/03 2022 Q13 [14]}}