OCR H240/03 2022 June — Question 3 4 marks

Exam BoardOCR
ModuleH240/03 (Pure Mathematics and Mechanics)
Year2022
SessionJune
Marks4
PaperDownload PDF ↗
TopicCircles
TypeCircle from diameter endpoints
DifficultyModerate -0.8 This is a straightforward application of the circle-from-diameter formula requiring finding the midpoint (center) and radius, then expanding to the required form. It involves only routine coordinate geometry techniques with no problem-solving insight needed, making it easier than average but not trivial due to the algebraic manipulation required.
Spec1.03d Circles: equation (x-a)^2+(y-b)^2=r^21.03e Complete the square: find centre and radius of circle

The points \(P\) and \(Q\) have coordinates \((2, -5)\) and \((3, 1)\) respectively. Determine the equation of the circle that has \(PQ\) as a diameter. Give your answer in the form \(x^2 + y^2 + ax + by + c = 0\), where \(a\), \(b\) and \(c\) are integers. [4]

The points $P$ and $Q$ have coordinates $(2, -5)$ and $(3, 1)$ respectively.

Determine the equation of the circle that has $PQ$ as a diameter. Give your answer in the form $x^2 + y^2 + ax + by + c = 0$, where $a$, $b$ and $c$ are integers. [4]

\hfill \mbox{\textit{OCR H240/03 2022 Q3 [4]}}