| Exam Board | OCR |
|---|---|
| Module | H240/03 (Pure Mathematics and Mechanics) |
| Year | 2021 |
| Session | November |
| Marks | 3 |
| Paper | Download PDF ↗ |
| Topic | Constant acceleration (SUVAT) |
| Type | Find acceleration from distances/times |
| Difficulty | Moderate -0.8 This is a straightforward constant acceleration kinematics problem requiring direct application of standard SUVAT equations. Part (a) uses v=u+at with given values, and part (b) uses v²=u²+2as. Both parts involve routine substitution with no problem-solving insight required, making it easier than average but not trivial since it requires correct equation selection and careful arithmetic. |
| Spec | 3.02d Constant acceleration: SUVAT formulae |
There are three checkpoints, $A$, $B$ and $C$, in that order, on a straight horizontal road. A car travels along the road, in the direction from $A$ to $C$, with constant acceleration. The car takes 20 s to travel from $B$ to $C$. The speed of the car at $B$ is 14 m s$^{-1}$ and the speed of the car at $C$ is 18 m s$^{-1}$.
\begin{enumerate}[label=(\alph*)]
\item Find the acceleration of the car. [1]
\end{enumerate}
It is given that the distance between $A$ and $B$ is 330 m.
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Determine the speed of the car at $A$. [2]
\end{enumerate}
\hfill \mbox{\textit{OCR H240/03 2021 Q9 [3]}}