OCR H240/03 2019 June — Question 4 14 marks

Exam BoardOCR
ModuleH240/03 (Pure Mathematics and Mechanics)
Year2019
SessionJune
Marks14
PaperDownload PDF ↗
TopicNumerical integration
TypeShow trapezium rule gives specific value
DifficultyStandard +0.3 This is a multi-part question covering standard A-level techniques: differentiation with product rule (part a), Newton-Raphson iteration (part b), trapezium rule (part c), and integration by parts (part d). While it requires multiple skills, each part follows routine procedures with no novel insights needed. The algebraic manipulation is straightforward, and the question structure guides students through each step clearly.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.05o Trigonometric equations: solve in given intervals1.05p Proof involving trig: functions and identities

\includegraphics{figure_4} The diagram shows the part of the curve \(y = 3x \sin 2x\) for which \(0 \leqslant x \leqslant \frac{1}{2}\pi\). The maximum point on the curve is denoted by \(P\).
  1. Show that the \(x\)-coordinate of \(P\) satisfies the equation \(\tan 2x + 2x = 0\). [3]
  2. Use the Newton-Raphson method, with a suitable initial value, to find the \(x\)-coordinate of \(P\), giving your answer correct to 4 decimal places. Show the result of each iteration. [4]
  3. The trapezium rule, with four strips of equal width, is used to find an approximation to $$\int_0^{\frac{1}{2}\pi} 3x \sin 2x \, dx.$$ Show that the result can be expressed as \(k\pi^2(\sqrt{2} + 1)\), where \(k\) is a rational number to be determined. [4]
    1. Evaluate \(\int_0^{\frac{1}{2}\pi} 3x \sin 2x \, dx\). [1]
    2. Hence determine whether using the trapezium rule with four strips of equal width gives an under- or over-estimate for the area of the region enclosed by the curve \(y = 3x \sin 2x\) and the \(x\)-axis for \(0 \leqslant x \leqslant \frac{1}{2}\pi\). [1]
    3. Explain briefly why it is not easy to tell from the diagram alone whether the trapezium rule with four strips of equal width gives an under- or over-estimate for the area of the region in this case. [1]

\includegraphics{figure_4}

The diagram shows the part of the curve $y = 3x \sin 2x$ for which $0 \leqslant x \leqslant \frac{1}{2}\pi$.

The maximum point on the curve is denoted by $P$.

\begin{enumerate}[label=(\alph*)]
\item Show that the $x$-coordinate of $P$ satisfies the equation $\tan 2x + 2x = 0$. [3]

\item Use the Newton-Raphson method, with a suitable initial value, to find the $x$-coordinate of $P$, giving your answer correct to 4 decimal places. Show the result of each iteration. [4]

\item The trapezium rule, with four strips of equal width, is used to find an approximation to
$$\int_0^{\frac{1}{2}\pi} 3x \sin 2x \, dx.$$

Show that the result can be expressed as $k\pi^2(\sqrt{2} + 1)$, where $k$ is a rational number to be determined. [4]

\item \begin{enumerate}[label=(\roman*)]
\item Evaluate $\int_0^{\frac{1}{2}\pi} 3x \sin 2x \, dx$. [1]

\item Hence determine whether using the trapezium rule with four strips of equal width gives an under- or over-estimate for the area of the region enclosed by the curve $y = 3x \sin 2x$ and the $x$-axis for $0 \leqslant x \leqslant \frac{1}{2}\pi$. [1]

\item Explain briefly why it is not easy to tell from the diagram alone whether the trapezium rule with four strips of equal width gives an under- or over-estimate for the area of the region in this case. [1]
\end{enumerate}
\end{enumerate}

\hfill \mbox{\textit{OCR H240/03 2019 Q4 [14]}}