CAIE Further Paper 2 2023 June — Question 2 7 marks

Exam BoardCAIE
ModuleFurther Paper 2 (Further Paper 2)
Year2023
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSecond order differential equations
TypeStandard non-homogeneous with polynomial RHS
DifficultyStandard +0.8 This is a standard second-order linear non-homogeneous differential equation requiring both complementary function (solving auxiliary equation with complex roots) and particular integral (trying polynomial form). While the method is systematic, it involves multiple steps including complex number manipulation, coefficient matching for a quadratic particular integral, and interpreting asymptotic behavior. This is typical Further Maths content but more involved than average A-level questions.
Spec4.10d Second order homogeneous: auxiliary equation method4.10e Second order non-homogeneous: complementary + particular integral

2 The variables \(x\) and \(y\) are related by the differential equation $$6 \frac { d ^ { 2 } x } { d t ^ { 2 } } + 5 \frac { d x } { d t } + x = t ^ { 2 } + 10 t + 13$$
  1. Find the general solution for \(x\) in terms of \(t\).
  2. State an approximate solution for large positive values of \(t\).

Question 2(a):
AnswerMarks Guidance
\(6m^2 + 5m + 1 = 0 \Rightarrow m = -\frac{1}{2}, -\frac{1}{3}\)M1 Auxiliary equation
\(x = Ae^{-\frac{1}{2}t} + Be^{-\frac{1}{3}t}\)A1 Complementary function. Allow with '\(x=\)' missing
\(x = p + qt + rt^2 \Rightarrow x' = q + 2rt \Rightarrow x'' = 2r\)B1 Particular integral and its derivatives
\(12r + 5q + 10rt + p + qt + rt^2 = t^2 + 10t + 13\)M1 Substitutes and equates coefficients
\(r = 1,\quad q = 0,\quad p = 1\)A1
\(x = Ae^{-\frac{1}{2}t} + Be^{-\frac{1}{3}t} + t^2 + 1\)A1 Must have \(x=\)
Question 2(b):
AnswerMarks Guidance
\(x = t^2 + 1\)B1FT Must have '\(x=\)'. Accept '\(x\) is approximately' but do not accept '\(x \rightarrow\)'. FT on their PI
## Question 2(a):

| $6m^2 + 5m + 1 = 0 \Rightarrow m = -\frac{1}{2}, -\frac{1}{3}$ | M1 | Auxiliary equation |
|---|---|---|
| $x = Ae^{-\frac{1}{2}t} + Be^{-\frac{1}{3}t}$ | A1 | Complementary function. Allow with '$x=$' missing |
| $x = p + qt + rt^2 \Rightarrow x' = q + 2rt \Rightarrow x'' = 2r$ | B1 | Particular integral and its derivatives |
| $12r + 5q + 10rt + p + qt + rt^2 = t^2 + 10t + 13$ | M1 | Substitutes and equates coefficients |
| $r = 1,\quad q = 0,\quad p = 1$ | A1 | |
| $x = Ae^{-\frac{1}{2}t} + Be^{-\frac{1}{3}t} + t^2 + 1$ | A1 | Must have $x=$ |

## Question 2(b):

| $x = t^2 + 1$ | B1FT | Must have '$x=$'. Accept '$x$ is approximately' but do not accept '$x \rightarrow$'. FT on their PI |

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2 The variables $x$ and $y$ are related by the differential equation

$$6 \frac { d ^ { 2 } x } { d t ^ { 2 } } + 5 \frac { d x } { d t } + x = t ^ { 2 } + 10 t + 13$$
\begin{enumerate}[label=(\alph*)]
\item Find the general solution for $x$ in terms of $t$.
\item State an approximate solution for large positive values of $t$.
\end{enumerate}

\hfill \mbox{\textit{CAIE Further Paper 2 2023 Q2 [7]}}