Challenging +1.8 This M5 question requires finding the reaction force component at the instant of release using rotational dynamics. Students must resolve the weight components perpendicular to PQ, apply the equation of rotational motion (torque = Iα) to find angular acceleration, then use this to find the required force component. While the moment of inertia is given, the multi-step process involving torque calculation, resolving forces from both the disc and particle, and careful geometric reasoning with the given sin β = 0.25 makes this significantly harder than routine mechanics problems but still within standard M5 scope.
A body consists of a uniform plane circular disc, of radius \(r\) and mass \(2m\), with a particle of mass \(3m\) attached to the circumference of the disc at the point \(P\).
The line \(PQ\) is a diameter of the disc. The body is free to rotate in a vertical plane about a fixed smooth horizontal axis, \(L\), which is perpendicular to the plane of the disc and passes through \(Q\). The body is held with \(QP\) making an angle \(\beta\) with the downward vertical through \(Q\), where \(\sin \beta = 0.25\), and released from rest. Find the magnitude of the component, perpendicular to \(PQ\), of the force acting on the body at \(Q\) at the instant when it is released.
[You may assume that the moment of inertia of the body about \(L\) is \(15mr^2\).]
[6]
A body consists of a uniform plane circular disc, of radius $r$ and mass $2m$, with a particle of mass $3m$ attached to the circumference of the disc at the point $P$.
The line $PQ$ is a diameter of the disc. The body is free to rotate in a vertical plane about a fixed smooth horizontal axis, $L$, which is perpendicular to the plane of the disc and passes through $Q$. The body is held with $QP$ making an angle $\beta$ with the downward vertical through $Q$, where $\sin \beta = 0.25$, and released from rest. Find the magnitude of the component, perpendicular to $PQ$, of the force acting on the body at $Q$ at the instant when it is released.
[You may assume that the moment of inertia of the body about $L$ is $15mr^2$.]
[6]
\hfill \mbox{\textit{Edexcel M5 2012 Q4 [6]}}