Edexcel M1 — Question 4 10 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks10
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TopicMomentum and Collisions
TypeCollision with friction after impact
DifficultyStandard +0.3 This is a standard two-part mechanics question combining conservation of momentum (routine application) with friction/kinematics (straightforward use of equations of motion). Part (a) is a direct momentum calculation with given final velocity for A. Part (b) requires working backwards from stopping distance using v² = u² + 2as and F = μR, but follows a well-practiced procedure. The 'show that' format and multi-step nature elevate it slightly above the most basic M1 questions, but it remains a textbook-style problem requiring no novel insight.
Spec3.03r Friction: concept and vector form3.03t Coefficient of friction: F <= mu*R model6.03b Conservation of momentum: 1D two particles

In a physics experiment, two balls \(A\) and \(B\), of mass \(4m\) and \(3m\) respectively, are travelling towards one another on a straight horizontal track. Both balls are travelling with speed 2 m s\(^{-1}\) immediately before they collide. As a result of the impact, \(A\) is brought to rest and the direction of motion of \(B\) is reversed. Modelling the track as smooth and the balls as particles,
  1. find the speed of \(B\) immediately after the collision. [3 marks]
A student notices that after the collision, \(B\) comes to rest 0.2 m from \(A\).
  1. Show that the coefficient of friction between \(B\) and the track is 0.113, correct to 3 decimal places. [7 marks]

(a) cons. of mom. \(4m \times 2 - 3m \times 2 = 0 + 3mv\)
AnswerMarks Guidance
\(2m = 3mv\) so \(v = \frac{2}{3}\) ms\(^{-1}\)M1 M1 A1
(b) \(R = mg\), \(F = ma\)
but \(F = \mu R\), so \(a = \frac{-\mu R}{m} = \frac{-\mu mg}{m} = -\mu g\)
use with \(u = \frac{2}{3}, v = 0, s = 0.2\)
\(v^2 = u^2 + 2as\) ∴ \(0 = \frac{4}{9} - 0.4\mu g\)
AnswerMarks Guidance
\(\mu = \frac{10}{9g} = 0.113\) (3dp)M1 M1 A1
**(a)** cons. of mom. $4m \times 2 - 3m \times 2 = 0 + 3mv$
$2m = 3mv$ so $v = \frac{2}{3}$ ms$^{-1}$ | M1 | M1 A1 |

**(b)** $R = mg$, $F = ma$
but $F = \mu R$, so $a = \frac{-\mu R}{m} = \frac{-\mu mg}{m} = -\mu g$
use with $u = \frac{2}{3}, v = 0, s = 0.2$
$v^2 = u^2 + 2as$ ∴ $0 = \frac{4}{9} - 0.4\mu g$
$\mu = \frac{10}{9g} = 0.113$ (3dp) | M1 | M1 A1 | M1 | M1 | M1 A1 | (10) |

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In a physics experiment, two balls $A$ and $B$, of mass $4m$ and $3m$ respectively, are travelling towards one another on a straight horizontal track. Both balls are travelling with speed 2 m s$^{-1}$ immediately before they collide.

As a result of the impact, $A$ is brought to rest and the direction of motion of $B$ is reversed.

Modelling the track as smooth and the balls as particles,

\begin{enumerate}[label=(\alph*)]
\item find the speed of $B$ immediately after the collision. [3 marks]
\end{enumerate}

A student notices that after the collision, $B$ comes to rest 0.2 m from $A$.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Show that the coefficient of friction between $B$ and the track is 0.113, correct to 3 decimal places. [7 marks]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1  Q4 [10]}}