| Exam Board | OCR MEI |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2008 |
| Session | January |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Forces, equilibrium and resultants |
| Type | Forces in vector form: kinematics extension |
| Difficulty | Moderate -0.8 This is a straightforward M1 mechanics question requiring direct application of F=ma to find acceleration vector, basic trigonometry (arctan) for angle, and constant acceleration kinematics (s=ut+½at²) with vectors. All three parts are routine calculations with no problem-solving insight needed, making it easier than average but not trivial due to the vector manipulation and multi-step nature. |
| Spec | 1.10d Vector operations: addition and scalar multiplication3.02e Two-dimensional constant acceleration: with vectors3.03d Newton's second law: 2D vectors |
The force acting on a particle of mass 1.5 kg is given by the vector $\begin{pmatrix} 6 \\ 9 \end{pmatrix}$ N.
\begin{enumerate}[label=(\roman*)]
\item Give the acceleration of the particle as a vector. [2]
\item Calculate the angle that the acceleration makes with the direction $\begin{pmatrix} 1 \\ 0 \end{pmatrix}$. [2]
\item At a certain point of its motion, the particle has a velocity of $\begin{pmatrix} -2 \\ 3 \end{pmatrix}$ m s$^{-1}$. Calculate the displacement of the particle over the next two seconds. [3]
\end{enumerate}
\hfill \mbox{\textit{OCR MEI M1 2008 Q2 [7]}}