| Exam Board | OCR |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2016 |
| Session | June |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Travel graphs |
| Type | Vertical motion under gravity |
| Difficulty | Moderate -0.8 This is a straightforward two-part kinematics question using standard SUVAT equations. Part (i) requires basic application of v²=u²+2as and v=u+at with g=10 or 9.8. Part (ii) applies the same equation with different acceleration. No problem-solving insight needed, just routine application of memorized formulas to clearly stated scenarios. |
| Spec | 3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form |
| Answer | Marks |
|---|---|
| Marks | Guidance |
| M1 | \(v^2 = u^2 +/-2gs\) with \(u=0\) |
| A1 | -ve final answer A0 |
| M1 | \(v = u+gt\) with \(u=0\) |
| A1 | Accept 10/7 |
| [4] | There are many alternatives, but following through of wrong answer is allowed only for method marks as the \(h\) and \(t\) values can be found independently. |
| Answer | Marks |
|---|---|
| Marks | Guidance |
| M1 | \(v^2 = 14^2 +/- 2as\), \(a \neq g\) |
| A1 | |
| A1 | |
| [3] |
## Part i
**Answer/Working:**
$14^2 = 2gh$
$h = 10$ m
$14 = gt$
$t = 1.43$ s
OR
$14 = gt$
$t = 1.43$ s
$h = 0x1.43 + 9.8x1.43^2/2$
$h = 10(0)$ m
| **Marks** | **Guidance** |
|-----------|-------------|
| M1 | $v^2 = u^2 +/-2gs$ with $u=0$ |
| A1 | -ve final answer A0 |
| M1 | $v = u+gt$ with $u=0$ |
| A1 | Accept 10/7 |
| [4] | There are many alternatives, but following through of wrong answer is allowed only for method marks as the $h$ and $t$ values can be found independently. |
## Part ii
**Answer/Working:**
$20^2 = 14^2 + 2a15$
$a = 6.8$ m s$^{-2}$
| **Marks** | **Guidance** |
|-----------|-------------|
| M1 | $v^2 = 14^2 +/- 2as$, $a \neq g$ |
| A1 | |
| A1 | |
| [3] | |
---A stone is released from rest on a bridge and falls vertically into a lake. The stone has velocity $14\text{ m s}^{-1}$ when it enters the lake.
\begin{enumerate}[label=(\roman*)]
\item Calculate the distance the stone falls before it enters the lake, and the time after its release when it enters the lake. [4]
\end{enumerate}
The lake is $15\text{ m}$ deep and the stone has velocity $20\text{ m s}^{-1}$ immediately before it reaches the bed of the lake.
\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item Given that there is no sudden change in the velocity of the stone when it enters the lake, find the acceleration of the stone while it is falling through the lake. [3]
\end{enumerate}
\hfill \mbox{\textit{OCR M1 2016 Q1 [7]}}