| Exam Board | OCR |
|---|---|
| Module | M1 (Mechanics 1) |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Travel graphs |
| Type | Distance from velocity-time graph |
| Difficulty | Moderate -0.8 This is a straightforward kinematics question requiring interpretation of a velocity-time graph. Students need to recognize that maximum distance occurs when velocity returns to zero, calculate displacement as area under the graph (with sign consideration), and find total distance by summing absolute areas. These are standard M1 techniques with no conceptual challenges beyond basic graph interpretation. |
| Spec | 3.02c Interpret kinematic graphs: gradient and area |
\includegraphics{figure_2}
A particle starts from the point $A$ and travels in a straight line. The diagram shows the $(t, v)$ graph, consisting of three straight line segments, for the motion of the particle during the interval $0 \leq t \leq 290$.
\begin{enumerate}[label=(\roman*)]
\item Find the value of $t$ for which the distance of the particle from $A$ is greatest. [2]
\item Find the displacement of the particle from $A$ when $t = 290$. [3]
\item Find the total distance travelled by the particle during the interval $0 \leq t \leq 290$. [2]
\end{enumerate}
\hfill \mbox{\textit{OCR M1 Q2 [7]}}