OCR M1 — Question 2 7 marks

Exam BoardOCR
ModuleM1 (Mechanics 1)
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicForces, equilibrium and resultants
TypeParticle with string at angle to wall
DifficultyModerate -0.3 This is a standard M1 mechanics problem involving resolving forces on an object in equilibrium relative to an accelerating reference frame. Part (i) is straightforward application of F=ma horizontally (0.08 × 1.25 = T sin α). Part (ii) requires resolving vertically (T cos α = 0.08g) then combining equations to find T. While it requires multiple steps and careful resolution of forces, it follows a very standard template for M1 string-tension problems with no novel insight needed.
Spec3.03c Newton's second law: F=ma one dimension3.03d Newton's second law: 2D vectors

\includegraphics{figure_2} An object of mass \(0.08\) kg is attached to one end of a light inextensible string. The other end of the string is attached to the underside of the roof inside a furniture van. The van is moving horizontally with constant acceleration \(1.25\) m s\(^{-2}\). The string makes a constant angle \(\alpha\) with the downward vertical and the tension in the string is \(T\) N (see diagram).
  1. By applying Newton's second law horizontally to the object, find the value of \(T \sin \alpha\). [2]
  2. Find the value of \(T\). [5]

\includegraphics{figure_2}

An object of mass $0.08$ kg is attached to one end of a light inextensible string. The other end of the string is attached to the underside of the roof inside a furniture van. The van is moving horizontally with constant acceleration $1.25$ m s$^{-2}$. The string makes a constant angle $\alpha$ with the downward vertical and the tension in the string is $T$ N (see diagram).

\begin{enumerate}[label=(\roman*)]
\item By applying Newton's second law horizontally to the object, find the value of $T \sin \alpha$. [2]
\item Find the value of $T$. [5]
\end{enumerate}

\hfill \mbox{\textit{OCR M1  Q2 [7]}}