Edexcel C4 — Question 3 14 marks

Exam BoardEdexcel
ModuleC4 (Core Mathematics 4)
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration by Substitution
DifficultyStandard +0.3 Part (a) is a routine proof of a standard double angle formula. Part (b) is a standard trigonometric substitution integral with given limits, requiring careful execution but following a predictable method. Part (c) involves parametric differentiation with sec and ln functions, which is slightly more involved than basic parametric questions but still follows standard C4 techniques. Overall, this is a straightforward multi-part question testing standard C4 content with no novel insights required, making it slightly easier than average.
Spec1.05l Double angle formulae: and compound angle formulae1.07s Parametric and implicit differentiation1.08h Integration by substitution

  1. Use the identity for \(\cos(A + B)\) to prove that \(\cos 2A = 2\cos^2 A - 1\). [2]
  2. Use the substitution \(x = 2\sqrt{2} \sin \theta\) to prove that $$\int_2^{\sqrt{6}} \sqrt{(8 - x^2)} \, dx = \frac{1}{3}(\pi + 3\sqrt{3} - 6).$$ [7]
A curve is given by the parametric equations $$x = \sec \theta, \quad y = \ln(1 + \cos 2\theta), \quad 0 \leq \theta < \frac{\pi}{2}.$$
  1. Find an equation of the tangent to the curve at the point where \(\theta = \frac{\pi}{3}\). [5]

Question 3:
3
Question 3:
3
\begin{enumerate}[label=(\alph*)]
\item Use the identity for $\cos(A + B)$ to prove that $\cos 2A = 2\cos^2 A - 1$.
[2]

\item Use the substitution $x = 2\sqrt{2} \sin \theta$ to prove that
$$\int_2^{\sqrt{6}} \sqrt{(8 - x^2)} \, dx = \frac{1}{3}(\pi + 3\sqrt{3} - 6).$$
[7]
\end{enumerate}

A curve is given by the parametric equations
$$x = \sec \theta, \quad y = \ln(1 + \cos 2\theta), \quad 0 \leq \theta < \frac{\pi}{2}.$$

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item Find an equation of the tangent to the curve at the point where $\theta = \frac{\pi}{3}$.
[5]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C4  Q3 [14]}}