AQA C4 2010 June — Question 4 7 marks

Exam BoardAQA
ModuleC4 (Core Mathematics 4)
Year2010
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGeneralised Binomial Theorem
TypeFactoring out constants before expansion
DifficultyModerate -0.3 This is a straightforward binomial expansion question testing standard C4 technique. Part (a)(i) is direct application of the formula, (a)(ii) requires factoring out 16 first, and part (b) is simple substitution. The multi-step structure adds slight complexity, but each step follows a routine procedure with no problem-solving insight required, making it slightly easier than average.
Spec1.04c Extend binomial expansion: rational n, |x|<11.04d Binomial expansion validity: convergence conditions

    1. Find the binomial expansion of \((1 + x)^{\frac{3}{2}}\) up to and including the term in \(x^2\). [2 marks]
    2. Find the binomial expansion of \((16 + 9x)^{\frac{3}{2}}\) up to and including the term in \(x^2\). [3 marks]
  1. Use your answer to part (a)(ii) to show that \(13^{\frac{3}{2}} \approx 46 + \frac{a}{b}\), stating the values of the integers \(a\) and \(b\). [2 marks]

4(a)(i)
AnswerMarks Guidance
\((1 + x)^{\frac{1}{3}} = 1 + \frac{1}{3}x + kx^2\)M1
\(= 1 + \frac{1}{3}x + \frac{3}{8}x^2\)A1 2 marks
4(a)(ii)
AnswerMarks Guidance
\((16 + 9x)^{\frac{1}{3}} = 16^{\frac{1}{3}}\left(1 + \frac{9}{16}x\right)^{\frac{1}{3}}\)B1
\(= k\left(1 + \frac{3}{16}x + \frac{1}{8}(\frac{9}{16}x)^2\right)\)M1 \(x\) replaced by \(\frac{9}{16}x\) or start binomial again; Condone missing brackets
\(= 64 + 54x + \frac{243}{32}x^2\)A1 3 marks
4(b)
AnswerMarks Guidance
\(x = -\frac{1}{3}\); \(13^{\frac{3}{2}} = 46 + \frac{27}{32}\)M1 A1 2 marks
**4(a)(i)**
$(1 + x)^{\frac{1}{3}} = 1 + \frac{1}{3}x + kx^2$ | M1

$= 1 + \frac{1}{3}x + \frac{3}{8}x^2$ | A1 | 2 marks

**4(a)(ii)**
$(16 + 9x)^{\frac{1}{3}} = 16^{\frac{1}{3}}\left(1 + \frac{9}{16}x\right)^{\frac{1}{3}}$ | B1

$= k\left(1 + \frac{3}{16}x + \frac{1}{8}(\frac{9}{16}x)^2\right)$ | M1 | $x$ replaced by $\frac{9}{16}x$ or start binomial again; Condone missing brackets

$= 64 + 54x + \frac{243}{32}x^2$ | A1 | 3 marks | Accept 7.59375$x^2$

**4(b)**
$x = -\frac{1}{3}$; $13^{\frac{3}{2}} = 46 + \frac{27}{32}$ | M1 A1 | 2 marks | Use $x = -\frac{1}{3}$; 46 seen with $a = 27$, $b = 32$, or $\left(\frac{k \times 27}{k \times 32}\right)$

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\begin{enumerate}[label=(\alph*)]
\item 
\begin{enumerate}[label=(\roman*)]
\item Find the binomial expansion of $(1 + x)^{\frac{3}{2}}$ up to and including the term in $x^2$. [2 marks]

\item Find the binomial expansion of $(16 + 9x)^{\frac{3}{2}}$ up to and including the term in $x^2$. [3 marks]
\end{enumerate}

\item Use your answer to part (a)(ii) to show that $13^{\frac{3}{2}} \approx 46 + \frac{a}{b}$, stating the values of the integers $a$ and $b$. [2 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA C4 2010 Q4 [7]}}