OCR MEI C3 2011 June — Question 6 6 marks

Exam BoardOCR MEI
ModuleC3 (Core Mathematics 3)
Year2011
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicImplicit equations and differentiation
TypeFind dy/dx at a point
DifficultyStandard +0.3 This is a straightforward implicit differentiation question with standard verification. Part (i) is trivial substitution (1 mark). Part (ii) requires applying implicit differentiation to sin 2x + cos y = √3, which is a routine C3 technique, followed by substituting coordinates to find a numerical gradient. The chain rule application is standard and the algebra is clean, making this slightly easier than the average A-level question.
Spec1.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.07s Parametric and implicit differentiation

A curve is defined by the equation \(\sin 2x + \cos y = \sqrt{3}\).
  1. Verify that the point P \((\frac{\pi}{6}, \frac{\pi}{6})\) lies on the curve. [1]
  2. Find \(\frac{dy}{dx}\) in terms of \(x\) and \(y\). Hence find the gradient of the curve at the point P. [5]

A curve is defined by the equation $\sin 2x + \cos y = \sqrt{3}$.

\begin{enumerate}[label=(\roman*)]
\item Verify that the point P $(\frac{\pi}{6}, \frac{\pi}{6})$ lies on the curve. [1]

\item Find $\frac{dy}{dx}$ in terms of $x$ and $y$.

Hence find the gradient of the curve at the point P. [5]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI C3 2011 Q6 [6]}}