OCR C3 2009 June — Question 3 6 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2009
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeCompound angle with reciprocal functions
DifficultyStandard +0.3 This is a straightforward trigonometric identity question requiring knowledge of sec²θ = 1 + tan²θ and the tan(α+β) formula. Part (i) reduces to a simple linear equation after substitution, and part (ii) is direct formula application. The algebraic manipulation is routine with no conceptual challenges beyond standard C3 content.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.05l Double angle formulae: and compound angle formulae

The angles \(\alpha\) and \(\beta\) are such that $$\tan \alpha = m + 2 \quad \text{and} \quad \tan \beta = m,$$ where \(m\) is a constant.
  1. Given that \(\sec^2 \alpha - \sec^2 \beta = 16\), find the value of \(m\). [3]
  2. Hence find the exact value of \(\tan(\alpha + \beta)\). [3]

The angles $\alpha$ and $\beta$ are such that
$$\tan \alpha = m + 2 \quad \text{and} \quad \tan \beta = m,$$
where $m$ is a constant.
\begin{enumerate}[label=(\roman*)]
\item Given that $\sec^2 \alpha - \sec^2 \beta = 16$, find the value of $m$. [3]
\item Hence find the exact value of $\tan(\alpha + \beta)$. [3]
\end{enumerate}

\hfill \mbox{\textit{OCR C3 2009 Q3 [6]}}