OCR C3 2010 January — Question 2 8 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2010
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeMultiple independent equations — all direct solve
DifficultyStandard +0.3 This is a standard C3 trigonometric equation question requiring double angle formulas and reciprocal identities. Part (i) uses sin 2θ = 2sin θ cos θ and leads to a quadratic in sin θ. Part (ii) requires recognizing cosec²θ = 1/sin²θ and rearranging. Both are routine applications of A-level identities with straightforward algebraic manipulation, making this slightly easier than average.
Spec1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

The angle \(\theta\) is such that \(0° < \theta < 90°\).
  1. Given that \(\theta\) satisfies the equation \(6 \sin 2\theta = 5 \cos \theta\), find the exact value of \(\sin \theta\). [3]
  2. Given instead that \(\theta\) satisfies the equation \(8 \cos \theta \cosec^2 \theta = 3\), find the exact value of \(\cos \theta\). [5]

The angle $\theta$ is such that $0° < \theta < 90°$.

\begin{enumerate}[label=(\roman*)]
\item Given that $\theta$ satisfies the equation $6 \sin 2\theta = 5 \cos \theta$, find the exact value of $\sin \theta$. [3]
\item Given instead that $\theta$ satisfies the equation $8 \cos \theta \cosec^2 \theta = 3$, find the exact value of $\cos \theta$. [5]
\end{enumerate}

\hfill \mbox{\textit{OCR C3 2010 Q2 [8]}}