AQA C3 2011 June — Question 5 8 marks

Exam BoardAQA
ModuleC3 (Core Mathematics 3)
Year2011
SessionJune
Marks8
PaperDownload PDF ↗
TopicComposite & Inverse Functions
TypeDetermine if inverse exists
DifficultyModerate -0.3 This is a straightforward C3 functions question testing standard concepts: explaining why a function lacks an inverse (many-to-one), finding an inverse by swapping and rearranging, stating range from domain, and solving a composite function equation. All parts are routine textbook exercises requiring no novel insight, making it slightly easier than average.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02v Inverse and composite functions: graphs and conditions for existence

The functions f and g are defined with their respective domains by $$f(x) = x^2 \quad \text{for all real values of } x$$ $$g(x) = \frac{1}{2x + 1} \quad \text{for real values of } x, \quad x \neq -0.5$$
  1. Explain why f does not have an inverse. [1]
  2. The inverse of g is \(g^{-1}\). Find \(g^{-1}(x)\). [3]
  3. State the range of \(g^{-1}\). [1]
  4. Solve the equation \(fg(x) = g(x)\). [3]

The functions f and g are defined with their respective domains by
$$f(x) = x^2 \quad \text{for all real values of } x$$
$$g(x) = \frac{1}{2x + 1} \quad \text{for real values of } x, \quad x \neq -0.5$$

\begin{enumerate}[label=(\alph*)]
\item Explain why f does not have an inverse. [1]

\item The inverse of g is $g^{-1}$. Find $g^{-1}(x)$. [3]

\item State the range of $g^{-1}$. [1]

\item Solve the equation $fg(x) = g(x)$. [3]
\end{enumerate}

\hfill \mbox{\textit{AQA C3 2011 Q5 [8]}}