OCR MEI C2 2016 June — Question 11 12 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Year2016
SessionJune
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Equations & Modelling
Typelog(y) vs x: convert and interpret
DifficultyModerate -0.3 This is a standard C2 logarithmic transformation question requiring routine application of log laws to linearise exponential data, followed by drawing a graph and reading off gradient/intercept. Part (iii) is direct substitution. While it involves multiple steps (8 marks for part ii), each step follows a well-practiced procedure with no novel problem-solving required, making it slightly easier than average.
Spec1.06f Laws of logarithms: addition, subtraction, power rules1.06h Logarithmic graphs: reduce y=ax^n and y=kb^x to linear form2.02c Scatter diagrams and regression lines

There are many different flu viruses. The numbers of flu viruses detected in the first few weeks of the 2012–2013 flu epidemic in the UK were as follows.
Week12345678910
Number of flu viruses710243240386396234480
These data may be modelled by an equation of the form \(y = a \times 10^{bt}\), where \(y\) is the number of flu viruses detected in week \(t\) of the epidemic, and \(a\) and \(b\) are constants to be determined.
  1. Explain why this model leads to a straight-line graph of \(\log_{10} y\) against \(t\). State the gradient and intercept of this graph in terms of \(a\) and \(b\). [3]
  2. Complete the values of \(\log_{10} y\) in the table, draw the graph of \(\log_{10} y\) against \(t\), and draw by eye a line of best fit for the data. Hence determine the values of \(a\) and \(b\) and the equation for \(y\) in terms of \(t\) for this model. [8]
During the decline of the epidemic, an appropriate model was $$y = 921 \times 10^{-0.137w},$$ where \(y\) is the number of flu viruses detected in week \(w\) of the decline.
  1. Use this to find the number of viruses detected in week 4 of the decline. [1]

There are many different flu viruses. The numbers of flu viruses detected in the first few weeks of the 2012–2013 flu epidemic in the UK were as follows.

\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|}
\hline
Week & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\
\hline
Number of flu viruses & 7 & 10 & 24 & 32 & 40 & 38 & 63 & 96 & 234 & 480 \\
\hline
\end{tabular}

These data may be modelled by an equation of the form $y = a \times 10^{bt}$, where $y$ is the number of flu viruses detected in week $t$ of the epidemic, and $a$ and $b$ are constants to be determined.

\begin{enumerate}[label=(\roman*)]
\item Explain why this model leads to a straight-line graph of $\log_{10} y$ against $t$. State the gradient and intercept of this graph in terms of $a$ and $b$. [3]

\item Complete the values of $\log_{10} y$ in the table, draw the graph of $\log_{10} y$ against $t$, and draw by eye a line of best fit for the data.

Hence determine the values of $a$ and $b$ and the equation for $y$ in terms of $t$ for this model. [8]
\end{enumerate}

During the decline of the epidemic, an appropriate model was

$$y = 921 \times 10^{-0.137w},$$

where $y$ is the number of flu viruses detected in week $w$ of the decline.

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{2}
\item Use this to find the number of viruses detected in week 4 of the decline. [1]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI C2 2016 Q11 [12]}}