OCR C2 — Question 4 8 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSine and Cosine Rules
TypeTriangle with trigonometric identities
DifficultyStandard +0.3 This is a straightforward application of the cosine rule followed by basic trigonometry and parallel line angle properties. Part (i) is a standard cosine rule calculation with given answer to verify, plus Pythagoras identity. Part (ii) requires recognizing that alternate angles are equal when AD || BC, making it a routine exercise. The multi-step nature and 8 marks elevate it slightly above average, but no novel insight is required.
Spec1.05b Sine and cosine rules: including ambiguous case1.05c Area of triangle: using 1/2 ab sin(C)

\includegraphics{figure_4} In the diagram, \(ABCD\) is a quadrilateral in which \(AD\) is parallel to \(BC\). It is given that \(AB = 9\), \(BC = 6\), \(CA = 5\) and \(CD = 15\).
  1. Show that \(\cos BCA = -\frac{1}{3}\), and hence find the value of \(\sin BCA\). [4]
  2. Find the angle \(ADC\) correct to the nearest \(0.1°\). [4]

\includegraphics{figure_4}

In the diagram, $ABCD$ is a quadrilateral in which $AD$ is parallel to $BC$. It is given that $AB = 9$, $BC = 6$, $CA = 5$ and $CD = 15$.

\begin{enumerate}[label=(\roman*)]
\item Show that $\cos BCA = -\frac{1}{3}$, and hence find the value of $\sin BCA$. [4]

\item Find the angle $ADC$ correct to the nearest $0.1°$. [4]
\end{enumerate}

\hfill \mbox{\textit{OCR C2  Q4 [8]}}