AQA C2 2009 June — Question 8 9 marks

Exam BoardAQA
ModuleC2 (Core Mathematics 2)
Year2009
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeEquation with 'show that' rewriting preliminary part
DifficultyModerate -0.3 This is a straightforward C2 trigonometry question testing standard identities and equation solving. Part (a) requires simple algebraic manipulation of a trigonometric expression (2 marks). Part (b) uses the Pythagorean identity sin²x + cos²x = 1 to transform the equation, then solving a quadratic in sin x - both routine techniques for C2 level with no novel insight required. The 9 total marks reflect length rather than conceptual difficulty.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals

  1. Given that \(\frac{\sin \theta - \cos \theta}{\cos \theta} = 4\), prove that \(\tan \theta = 5\). [2]
    1. Use an appropriate identity to show that the equation $$2 \cos^2 x - \sin x = 1$$ can be written as $$2 \sin^2 x + \sin x - 1 = 0$$ [2]
    2. Hence solve the equation $$2 \cos^2 x - \sin x = 1$$ giving all solutions in the interval \(0° \leq x \leq 360°\). [5]

Question 8:
8
Question 8:
8
\begin{enumerate}[label=(\alph*)]
\item Given that $\frac{\sin \theta - \cos \theta}{\cos \theta} = 4$, prove that $\tan \theta = 5$. [2]
\item \begin{enumerate}[label=(\roman*)]
\item Use an appropriate identity to show that the equation
$$2 \cos^2 x - \sin x = 1$$
can be written as
$$2 \sin^2 x + \sin x - 1 = 0$$ [2]
\item Hence solve the equation
$$2 \cos^2 x - \sin x = 1$$
giving all solutions in the interval $0° \leq x \leq 360°$. [5]
\end{enumerate}
\end{enumerate}

\hfill \mbox{\textit{AQA C2 2009 Q8 [9]}}