| Exam Board | OCR MEI |
|---|---|
| Module | C1 (Core Mathematics 1) |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Indices and Surds |
| Type | Evaluate numerical powers |
| Difficulty | Easy -1.8 This is a straightforward recall question testing basic index laws with no problem-solving required. Part (i) is trivial (anything to power 0 equals 1), and part (ii) is a routine calculation requiring only the knowledge that 16^{-3/2} = 1/(16^{3/2}) = 1/64. This is simpler than the calibration example at -1.5 as it involves fewer steps and more basic manipulation. |
| Spec | 1.02a Indices: laws of indices for rational exponents |
| Answer | Marks |
|---|---|
| 9 | (ii) |
| (iiii)) 1/64 | 1 |
| 3 | M1 for dealing correctly with each of |
| Answer | Marks |
|---|---|
| or M1 for 1/163/2 or 43 or −43 or 4-3 etc | 4 |
Question 9:
9 | (ii)
(iiii)) 1/64 | 1
3 | M1 for dealing correctly with each of
reciprocal, square root and cubing
(allow 3 only for 1/64)
eg M2 for 64 or −64 or 1/√4096 or ¼3
or M1 for 1/163/2 or 43 or −43 or 4-3 etc | 4\begin{enumerate}[label=(\roman*)]
\item Write down the value of $\left(\frac{1}{4}\right)^0$. [1]
\item Find the value of $16^{-\frac{3}{2}}$. [3]
\end{enumerate}
\hfill \mbox{\textit{OCR MEI C1 Q9 [4]}}