OCR MEI C1 — Question 10 5 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndices and Surds
TypeEvaluate numerical powers
DifficultyEasy -1.3 This is a straightforward C1 question testing basic index laws and algebraic manipulation. Part (i) requires simple recall of negative and fractional indices. Part (ii) involves routine simplification using power laws and cancellation. Both parts are standard textbook exercises with no problem-solving or conceptual challenge beyond mechanical application of rules.
Spec1.02a Indices: laws of indices for rational exponents
  1. Evaluate \(\left(\frac{9}{16}\right)^{-\frac{1}{2}}\). [2]
  2. Simplify \(\frac{(2ac^2)^3 \times 9a^2c}{36a^4c^{12}}\). [3]
Question 10:
AnswerMarks Guidance
10(ii) /3 isw 2
M1 for numerator or denominator
3 1
correct or for or oe or for
4 3
 
4
1
162
soi
 
AnswerMarks
 9 M1 for just −4/3;
allow M1 for 16 =4 and 9 =3soi;
condone missing brackets
AnswerMarks
102a
(ii) or 2ac−5
AnswerMarks Guidance
c53 B1 for each ‘term’ correct;
mark final answer;
if B0, then SC1 for (2ac2)3 = 8a3c6 or
AnswerMarks
72a5c7 seencondone a1;
condone multiplication signs but 0 for addition signs
Question 10:
10 | (ii) /3 isw | 2 | condone ±4/3;
M1 for numerator or denominator
3 1
correct or for or oe or for
4 3
 
4
1
162
soi
 
 9  | M1 for just −4/3;
allow M1 for 16 =4 and 9 =3soi;
condone missing brackets
10 | 2a
(ii) or 2ac−5
c5 | 3 | B1 for each ‘term’ correct;
mark final answer;
if B0, then SC1 for (2ac2)3 = 8a3c6 or
72a5c7 seen | condone a1;
condone multiplication signs but 0 for addition signs
\begin{enumerate}[label=(\roman*)]
\item Evaluate $\left(\frac{9}{16}\right)^{-\frac{1}{2}}$. [2]
\item Simplify $\frac{(2ac^2)^3 \times 9a^2c}{36a^4c^{12}}$. [3]
\end{enumerate}

\hfill \mbox{\textit{OCR MEI C1  Q10 [5]}}
This paper (11 questions)
View full paper
Q1 4 Q2 5 Q3 4 Q4 5 Q5 4 Q6 4 Q7 5 Q8 5 Q9 3 Q10 5 Q11 4