OCR MEI C1 — Question 3 4 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSolving quadratics and applications
TypeQuadratic in higher integer powers
DifficultyModerate -0.8 This is a straightforward two-part question requiring factorization of a simple quadratic (y-3)(y-4)=0, then substitution y=x² to solve the quartic. Both parts are routine C1 techniques with no problem-solving insight needed, making it easier than average but not trivial since it requires recognizing the substitution pattern.
Spec1.02f Solve quadratic equations: including in a function of unknown

Solve the equation \(y^2 - 7y + 12 = 0\). Hence solve the equation \(x^4 - 7x^2 + 12 = 0\). [4]

Question 3:
AnswerMarks
3(y − 3)(y − 4) [= 0]
y = 3 or 4 cao
AnswerMarks
x=± 3 or ±2 caoM1
A1
AnswerMarks
B2for factors giving two terms correct or
attempt at quadratic formula or
completing square
or B2 (both roots needed)
B1 for 2 roots correct or ft their y
AnswerMarks
(condone √ 3 and √ 4 for B1)4
Question 3:
3 | (y − 3)(y − 4) [= 0]
y = 3 or 4 cao
x=± 3 or ±2 cao | M1
A1
B2 | for factors giving two terms correct or
attempt at quadratic formula or
completing square
or B2 (both roots needed)
B1 for 2 roots correct or ft their y
(condone √ 3 and √ 4 for B1) | 4
Solve the equation $y^2 - 7y + 12 = 0$.

Hence solve the equation $x^4 - 7x^2 + 12 = 0$. [4]

\hfill \mbox{\textit{OCR MEI C1  Q3 [4]}}