Easy -1.2 This is a straightforward application of perpendicular gradient rules (negative reciprocal) and point-slope form. It requires only two standard steps: finding m = -1/2, then using y - 1 = -1/2(x - 4). This is easier than average as it's a routine C1 exercise with no problem-solving element.
Find the equation of the line which is perpendicular to the line \(y = 2x - 5\) and which passes through the point \((4, 1)\). Give your answer in the form \(y = ax + b\). [3]
B2 for \(2y = -x + 6\) oe; or M1 for gradient \(= -\frac{1}{2}\) oe seen or used; and M1 for \(y - 1 = \) their \(m(x - 4)\); or M1 for \(y = \) their \(mx + c\) and \((4, 1)\) substituted; for 3 marks must be in form \(y = ax + b\)
$y = -0.5x + 3$ oe www isw | 3 | B2 for $2y = -x + 6$ oe; or M1 for gradient $= -\frac{1}{2}$ oe seen or used; and M1 for $y - 1 = $ their $m(x - 4)$; or M1 for $y = $ their $mx + c$ and $(4, 1)$ substituted; for 3 marks must be in form $y = ax + b$
Find the equation of the line which is perpendicular to the line $y = 2x - 5$ and which passes through the point $(4, 1)$. Give your answer in the form $y = ax + b$. [3]
\hfill \mbox{\textit{OCR MEI C1 2013 Q1 [3]}}