OCR C1 2006 June — Question 5 8 marks

Exam BoardOCR
ModuleC1 (Core Mathematics 1)
Year2006
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeCompound inequality with double bound
DifficultyModerate -0.8 Part (i) is a routine double inequality requiring simple algebraic manipulation (add 9, divide by 4). Part (ii) is a standard quadratic inequality requiring rearrangement to standard form, factorization, and sign analysis—all textbook procedures for C1. The 8 total marks reflect straightforward application of basic techniques with no problem-solving insight required, making this easier than average.
Spec1.02g Inequalities: linear and quadratic in single variable1.02h Express solutions: using 'and', 'or', set and interval notation

Solve the inequalities
  1. \(1 < 4x - 9 < 5\), [3]
  2. \(y^2 \geq 4y + 5\). [5]

(i)
AnswerMarks Guidance
\(1 < 4x - 9 < 5\)M1 2 equations or inequalities both dealing with all 3 terms
\(10 < 4x < 14\)M1
\(2.5 < x < 3.5\)A1 3 marks; 2.5 and 3.5 seen oe
(ii)
AnswerMarks Guidance
\(y^2 \geq 4y + 5\)B1
\(y^2 - 4y - 5 \geq 0\)M1 \(y^2 - 4y - 5 = 0\) soi; Correct method to solve quadratic
\((y-5)(y+1) \geq 0\)A1
\(y \leq -1, y \geq 5\)M1 Correct method to solve inequality; -1, 5 (SR If both values obtained from trial and improvement, award B3)
\(y \leq -1, y \geq 5\)A1 5 marks total
## (i)
$1 < 4x - 9 < 5$ | M1 | 2 equations or inequalities both dealing with all 3 terms
$10 < 4x < 14$ | M1 |
$2.5 < x < 3.5$ | A1 | 3 marks; 2.5 and 3.5 seen oe

## (ii)
$y^2 \geq 4y + 5$ | B1 |
$y^2 - 4y - 5 \geq 0$ | M1 | $y^2 - 4y - 5 = 0$ soi; Correct method to solve quadratic
$(y-5)(y+1) \geq 0$ | A1 |
$y \leq -1, y \geq 5$ | M1 | Correct method to solve inequality; -1, 5 (SR If both values obtained from trial and improvement, award B3)

$y \leq -1, y \geq 5$ | A1 | 5 marks total

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Solve the inequalities
\begin{enumerate}[label=(\roman*)]
\item $1 < 4x - 9 < 5$, [3]
\item $y^2 \geq 4y + 5$. [5]
\end{enumerate}

\hfill \mbox{\textit{OCR C1 2006 Q5 [8]}}