Edexcel D1 2005 January — Question 6 14 marks

Exam BoardEdexcel
ModuleD1 (Decision Mathematics 1)
Year2005
SessionJanuary
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNetwork Flows
TypeState maximum flow along specific routes
DifficultyModerate -0.8 This is a standard textbook application of the max-flow min-cut algorithm with clear step-by-step instructions. Parts (a)-(b) involve simple path identification, part (c) applies the labelling procedure mechanically, and the proof in (c)(iii) requires stating a standard result (max-flow = min-cut). While multi-part with 14 marks total, it requires only routine application of a well-defined algorithm with no novel problem-solving or insight.
Spec7.04f Network problems: choosing appropriate algorithm

\includegraphics{figure_4} Figure 4 shows a capacitated directed network. The number on each arc is its capacity.
  1. State the maximum flow along
    1. \(SADT\),
    2. \(SCET\),
    3. \(SBFT\). [2]
  2. Show these maximum flows on Diagram 1 in the answer book. [1]
Take your answer to part (b) as the initial flow pattern.
    1. Use the labelling procedure to find a maximum flow from \(S\) to \(T\). Your working should be shown on Diagram 2 in the answer book. List each flow-augmenting route you use, together with its flow. [5]
    2. Draw your final flow pattern on Diagram 3 in the answer book. [2]
    3. Prove that your flow is maximal. [3]
  1. Give an example of a practical situation that could have been modelled by the original network. [1]

Part (a)
AnswerMarks Guidance
S ∩ D T − 8S ⊆ E T − 11 S ⊆ F T − 9
Part (b)
AnswerMarks
Diagram showing network with flows labeledB1 (3)
Part (c)
Part (i)
AnswerMarks Guidance
Examples: \(SACDT - 2\), \(SCEFT - 6\), \(SCEFT - 1\), \(SACFT - 1\)M1 A1 A1 (2) Maximum flow = 6
Part (ii)
AnswerMarks
Network diagram with flow values labeled, e.g., A→D: 8, D→T: 10M1 A1 (2)
Part (iii)
AnswerMarks
Maximum flow-minimum cut theorem: Cut \(\{SACEF\}\{BDFT\}\)M1 A2, 0 (3)
Part (d)
AnswerMarks
Idea of directed flow through system of arcs from S ⊆ TB1 (1)
## Part (a)
S ∩ D T − 8 | S ⊆ E T − 11 | S ⊆ F T − 9 | 8, 2, 1, 0

## Part (b)
Diagram showing network with flows labeled | B1 (3)

## Part (c)
### Part (i)
Examples: $SACDT - 2$, $SCEFT - 6$, $SCEFT - 1$, $SACFT - 1$ | M1 A1 A1 (2) | Maximum flow = 6

### Part (ii)
Network diagram with flow values labeled, e.g., A→D: 8, D→T: 10 | M1 A1 (2)

### Part (iii)
Maximum flow-minimum cut theorem: Cut $\{SACEF\}\{BDFT\}$ | M1 A2, 0 (3)

## Part (d)
Idea of directed flow through system of arcs from S ⊆ T | B1 (1)

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\includegraphics{figure_4}

Figure 4 shows a capacitated directed network. The number on each arc is its capacity.

\begin{enumerate}[label=(\alph*)]
\item State the maximum flow along
\begin{enumerate}[label=(\roman*)]
\item $SADT$,
\item $SCET$,
\item $SBFT$. [2]
\end{enumerate}

\item Show these maximum flows on Diagram 1 in the answer book. [1]
\end{enumerate}

Take your answer to part (b) as the initial flow pattern.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item \begin{enumerate}[label=(\roman*)]
\item Use the labelling procedure to find a maximum flow from $S$ to $T$. Your working should be shown on Diagram 2 in the answer book. List each flow-augmenting route you use, together with its flow. [5]

\item Draw your final flow pattern on Diagram 3 in the answer book. [2]

\item Prove that your flow is maximal. [3]
\end{enumerate}

\item Give an example of a practical situation that could have been modelled by the original network. [1]
\end{enumerate}

\hfill \mbox{\textit{Edexcel D1 2005 Q6 [14]}}