Edexcel D1 2003 January — Question 7 14 marks

Exam BoardEdexcel
ModuleD1 (Decision Mathematics 1)
Year2003
SessionJanuary
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNetwork Flows
TypeAdd supersource and/or supersink
DifficultyStandard +0.3 This is a standard D1 max-flow problem using the labelling procedure (Ford-Fulkerson algorithm). While it requires multiple steps and careful bookkeeping, it's a routine application of a well-defined algorithm taught in the module. The supersource/supersink addition in part (a) is textbook standard, and verifying maximality using a cut is straightforward. Slightly above average difficulty due to the multi-source/multi-sink setup and the 9 marks for part (b), but no novel insight required.
Spec7.04f Network problems: choosing appropriate algorithm

\includegraphics{figure_4} Figure 4 shows a capacitated directed network. The number on each arc is its capacity. The numbers in circles show a feasible flow from sources \(A\) and \(B\) to sinks \(I\), \(J\) and \(K\). Take this as the initial flow pattern.
  1. On Diagram 1 in the answer booklet, add a supersource \(S\) and a supersink \(W\) to obtain a capacitated network with a single source and single sink. State the minimum capacities of the arcs you have added. [3]
    1. Use the given initial flow and the labelling procedure on Diagram 2 to find the maximum flow through the network. You must list each flow-augmenting route you use together with its flow.
    2. Verify that your flow is maximal.
    [9]
  2. Show your maximum flow pattern on Diagram 3. [2]

Question 7:
7
8. (a)
(b)
AnswerMarks
(c)2x + 3y + 4z ≤ 8
3x + 3y + z ≤ 10
P = 8x + 9y + 5z
b.v x y z r s Value
r 2 3 4 1 0 8
s 3 3 1 0 1 10
P −8 −9 −5 0 0 0
b.v x y z r s Value
y 2 1 4 1 0 R ÷ 3
3 3 3 3 1
s 1 0 −3 −1 1 2 R – 3R
2 1
P −2 0 7 3 0 24 R + 9R
3 1
b.v x y z r s Value
y 0 1 10 1 −2 4 R 1 − 2 R 2
3 3 3 3
x 1 0 −3 −1 1 2
P 0 0 1 1 2 28 R + 2R
3 2
P = 28
x = 2, y = 4
3
AnswerMarks
z = 0, r = 0, s = 0B1
B1
B1 (3)
M1
A1
M1
A1
M1
A1
M1
A1 (8)
M1
A1
A1 (3)
(14 marks)
AnswerMarks Guidance
b.vx y
r2 3
s3 3
P−8 −9
b.vx y
y2
31 4
31
30 3
s1 0
P−2 0
b.vx y
y0 1
31 −2
34
3
AnswerMarks Guidance
x1 0
P0 0
Question 7:
7
8. (a)
(b)
(c) | 2x + 3y + 4z ≤ 8
3x + 3y + z ≤ 10
P = 8x + 9y + 5z
↓
b.v x y z r s Value
r 2 3 4 1 0 8
s 3 3 1 0 1 10
P −8 −9 −5 0 0 0
↓
b.v x y z r s Value
y 2 1 4 1 0 R ÷ 3
3 3 3 3 1
s 1 0 −3 −1 1 2 R – 3R
2 1
P −2 0 7 3 0 24 R + 9R
3 1
b.v x y z r s Value
y 0 1 10 1 −2 4 R 1 − 2 R 2
3 3 3 3
x 1 0 −3 −1 1 2
P 0 0 1 1 2 28 R + 2R
3 2
P = 28
x = 2, y = 4
3
z = 0, r = 0, s = 0 | B1
B1
B1 (3)
M1
A1
M1
A1
M1
A1
M1
A1 (8)
M1
A1
A1 (3)
(14 marks)
b.v | x | y | z | r | s | Value
r | 2 | 3 | 4 | 1 | 0 | 8
s | 3 | 3 | 1 | 0 | 1 | 10
P | −8 | −9 | −5 | 0 | 0 | 0
b.v | x | y | z | r | s | Value
y | 2
3 | 1 | 4
3 | 1
3 | 0 | 3
s | 1 | 0 | −3 | −1 | 1 | 2
P | −2 | 0 | 7 | 3 | 0 | 24
b.v | x | y | z | r | s | Value
y | 0 | 1 | 10
3 | 1 | −2
3 | 4
3
x | 1 | 0 | −3 | −1 | 1 | 2
P | 0 | 0 | 1 | 1 | 2 | 28
\includegraphics{figure_4}

Figure 4 shows a capacitated directed network. The number on each arc is its capacity. The numbers in circles show a feasible flow from sources $A$ and $B$ to sinks $I$, $J$ and $K$.
Take this as the initial flow pattern.

\begin{enumerate}[label=(\alph*)]
\item On Diagram 1 in the answer booklet, add a supersource $S$ and a supersink $W$ to obtain a capacitated network with a single source and single sink. State the minimum capacities of the arcs you have added.
[3]

\item \begin{enumerate}[label=(\roman*)]
\item Use the given initial flow and the labelling procedure on Diagram 2 to find the maximum flow through the network. You must list each flow-augmenting route you use together with its flow.

\item Verify that your flow is maximal.
\end{enumerate}
[9]

\item Show your maximum flow pattern on Diagram 3.
[2]
\end{enumerate}

\hfill \mbox{\textit{Edexcel D1 2003 Q7 [14]}}