Edexcel S2 2006 June — Question 2 7 marks

Exam BoardEdexcel
ModuleS2 (Statistics 2)
Year2006
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicContinuous Uniform Random Variables
TypeMultiple observations or trials
DifficultyModerate -0.3 This is a straightforward S2 question testing basic continuous uniform distribution calculations and binomial probability. Parts (a) and (b) require simple probability calculations using the uniform distribution formula, while part (c) involves recognizing a binomial distribution and computing P(X ≥ 11) where X ~ B(20, 0.75). All techniques are standard and routine for S2, though the multi-step nature and 7 total marks place it slightly below average difficulty overall.
Spec2.04c Calculate binomial probabilities2.04e Normal distribution: as model N(mu, sigma^2)5.03a Continuous random variables: pdf and cdf

The continuous random variable \(L\) represents the error, in mm, made when a machine cuts rods to a target length. The distribution of \(L\) is continuous uniform over the interval \([-4.0, 4.0]\). Find
  1. P\((L < -2.6)\), [1]
  2. P\((L < -3.0 \text{ or } L > 3.0)\). [2]
A random sample of 20 rods cut by the machine was checked.
  1. Find the probability that more than half of them were within 3.0 mm of the target length. [4]

AnswerMarks Guidance
(a) \(P(L < -2.6) = 1.4 \times \frac{1}{8} = \frac{7}{40}\) or 0.175 or equivalentB1
(b) \(P(L < -3.0 \text{ or } L > 3.0) = 2 \times (1 \times \frac{1}{8}) = \frac{1}{4}\)M1; A1 M1 for 1/8 seen
(c) \(P(\text{within 3mm}) = 1 - \frac{1}{4} = 0.75\), \(B(20, 0.75)\) recognises binomial. Using \(B(20,p)\)B1; M1
Let \(X\) represent number of rods within 3mm
AnswerMarks Guidance
\(P(X \leq 9 / p = 0.25)\) or \(1 - P(X \leq 10 / p = 0.75)\)M1
\(= 0.9861\)awrt 0.9861 A1
**(a)** $P(L < -2.6) = 1.4 \times \frac{1}{8} = \frac{7}{40}$ or 0.175 or equivalent | B1 |

**(b)** $P(L < -3.0 \text{ or } L > 3.0) = 2 \times (1 \times \frac{1}{8}) = \frac{1}{4}$ | M1; A1 | M1 for 1/8 seen

**(c)** $P(\text{within 3mm}) = 1 - \frac{1}{4} = 0.75$, $B(20, 0.75)$ recognises binomial. Using $B(20,p)$ | B1; M1 | 

Let $X$ represent number of rods within 3mm

$P(X \leq 9 / p = 0.25)$ or $1 - P(X \leq 10 / p = 0.75)$ | M1 |

$= 0.9861$ | awrt 0.9861 | A1 |
The continuous random variable $L$ represents the error, in mm, made when a machine cuts rods to a target length. The distribution of $L$ is continuous uniform over the interval $[-4.0, 4.0]$.

Find
\begin{enumerate}[label=(\alph*)]
\item P$(L < -2.6)$, [1]

\item P$(L < -3.0 \text{ or } L > 3.0)$. [2]
\end{enumerate}

A random sample of 20 rods cut by the machine was checked.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item Find the probability that more than half of them were within 3.0 mm of the target length. [4]
\end{enumerate}

\hfill \mbox{\textit{Edexcel S2 2006 Q2 [7]}}