Edexcel M3 2012 June — Question 1 9 marks

Exam BoardEdexcel
ModuleM3 (Mechanics 3)
Year2012
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable acceleration (1D)
TypeAcceleration as function of displacement (v dv/dx method)
DifficultyStandard +0.3 This is a standard M3 variable acceleration question requiring integration of an exponential velocity function and use of the chain rule for acceleration. Part (a) needs v(dv/dx) = a, and part (b) requires integrating v = dx/dt with given initial conditions. While it involves exponential functions and careful algebraic manipulation, the techniques are routine for M3 students and the question follows a familiar template, making it slightly easier than average overall.
Spec1.08a Fundamental theorem of calculus: integration as reverse of differentiation3.02f Non-uniform acceleration: using differentiation and integration

A particle \(P\) is moving along the positive \(x\)-axis. At time \(t = 0\), \(P\) is at the origin \(O\). At time \(t\) seconds, \(P\) is \(x\) metres from \(O\) and has velocity \(v = 2e^{-t}\) m s\(^{-1}\) in the direction of \(x\) increasing.
  1. Find the acceleration of \(P\) in terms of \(x\). [3]
  2. Find \(x\) in terms of \(t\). [6]

A particle $P$ is moving along the positive $x$-axis. At time $t = 0$, $P$ is at the origin $O$. At time $t$ seconds, $P$ is $x$ metres from $O$ and has velocity $v = 2e^{-t}$ m s$^{-1}$ in the direction of $x$ increasing.

\begin{enumerate}[label=(\alph*)]
\item Find the acceleration of $P$ in terms of $x$. [3]
\item Find $x$ in terms of $t$. [6]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M3 2012 Q1 [9]}}