Acceleration as function of displacement (v dv/dx method)

Questions where acceleration is given explicitly as a function of displacement x, requiring use of v dv/dx = a(x) to find velocity as a function of position.

5 questions · Standard +0.8

6.06a Variable force: dv/dt or v*dv/dx methods
Sort by: Default | Easiest first | Hardest first
CAIE M2 2005 June Q5
7 marks Standard +0.8
5 The acceleration of a particle moving in a straight line is \(( x - 2.4 ) \mathrm { m } \mathrm { s } ^ { - 2 }\) when its displacement from a fixed point \(O\) of the line is \(x \mathrm {~m}\). The velocity of the particle is \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\), and it is given that \(v = 2.5\) when \(x = 0\). Find
  1. an expression for \(v\) in terms of \(x\),
  2. the minimum value of \(v\).
CAIE M2 2007 June Q2
5 marks Standard +0.8
2 A particle starts from rest at \(O\) and travels in a straight line. Its acceleration is \(( 3 - 2 x ) \mathrm { ms } ^ { - 2 }\), where \(x \mathrm {~m}\) is the displacement of the particle from \(O\).
  1. Find the value of \(x\) for which the velocity of the particle reaches its maximum value.
  2. Find this maximum velocity.
CAIE M2 2011 June Q4
7 marks Standard +0.8
4 A particle \(P\) starts from rest at a point \(O\) and travels in a straight line. The acceleration of \(P\) is \(( 15 - 6 x ) \mathrm { m } \mathrm { s } ^ { - 2 }\), where \(x \mathrm {~m}\) is the displacement of \(P\) from \(O\).
  1. Find the value of \(x\) for which \(P\) reaches its maximum velocity, and calculate this maximum velocity.
  2. Calculate the acceleration of \(P\) when it is at instantaneous rest and \(x > 0\).
WJEC Further Unit 6 Specimen Q1
14 marks Challenging +1.2
  1. A ball of mass 0.4 kg is thrown vertically upwards from a point \(O\) with initial speed \(17 \mathrm {~ms} ^ { - 1 }\). When the ball is at a height of \(x \mathrm {~m}\) above \(O\) and its speed is \(v \mathrm {~ms} ^ { - 1 }\), the air resistance acting on the ball has magnitude \(0.01 v ^ { 2 } \mathrm {~N}\).
    1. Show that, as the ball is ascending, \(v\) satisfies the differential equation
    $$40 v \frac { \mathrm {~d} v } { \mathrm {~d} x } = - \left( 392 + v ^ { 2 } \right)$$
  2. Find an expression for \(v\) in terms of \(x\).
  3. Calculate, correct to two decimal places, the greatest height of the ball.
  4. State, with a reason, whether the speed of the ball when it returns to \(O\) is greater than \(17 \mathrm {~ms} ^ { - 1 }\), less than \(17 \mathrm {~ms} ^ { - 1 }\) or equal to \(17 \mathrm {~ms} ^ { - 1 }\).
Edexcel M3 2012 June Q1
9 marks Standard +0.3
A particle \(P\) is moving along the positive \(x\)-axis. At time \(t = 0\), \(P\) is at the origin \(O\). At time \(t\) seconds, \(P\) is \(x\) metres from \(O\) and has velocity \(v = 2e^{-t}\) m s\(^{-1}\) in the direction of \(x\) increasing.
  1. Find the acceleration of \(P\) in terms of \(x\). [3]
  2. Find \(x\) in terms of \(t\). [6]