Edexcel M2 2006 June — Question 2 6 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2006
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeAcceleration from power and speed
DifficultyModerate -0.3 Part (a) is a direct application of Power = Force × velocity requiring one calculation. Part (b) involves resolving forces on an incline and using P = Fv with Newton's second law, but follows a standard M2 template with straightforward arithmetic. The multi-step nature and incline component add slight complexity, but this remains a routine textbook exercise with no novel problem-solving required.
Spec6.02l Power and velocity: P = Fv

A car of mass 1200 kg moves along a straight horizontal road with a constant speed of 24 m s\(^{-1}\). The resistance to motion of the car has magnitude 600 N.
  1. Find, in kW, the rate at which the engine of the car is working. [2]
The car now moves up a hill inclined at \(\alpha\) to the horizontal, where \(\sin \alpha = \frac{1}{20}\). The resistance to motion of the car from non-gravitational forces remains of magnitude 600 N. The engine of the car now works at a rate of 30 kW.
  1. Find the acceleration of the car when its speed is 20 m s\(^{-1}\). [4]

A car of mass 1200 kg moves along a straight horizontal road with a constant speed of 24 m s$^{-1}$. The resistance to motion of the car has magnitude 600 N.

\begin{enumerate}[label=(\alph*)]
\item Find, in kW, the rate at which the engine of the car is working.
[2]
\end{enumerate}

The car now moves up a hill inclined at $\alpha$ to the horizontal, where $\sin \alpha = \frac{1}{20}$. The resistance to motion of the car from non-gravitational forces remains of magnitude 600 N. The engine of the car now works at a rate of 30 kW.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Find the acceleration of the car when its speed is 20 m s$^{-1}$.
[4]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2 2006 Q2 [6]}}