| Exam Board | Edexcel |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2014 |
| Session | January |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Impulse and momentum (advanced) |
| Type | Impulse from velocity change |
| Difficulty | Moderate -0.3 This is a straightforward application of the impulse-momentum theorem with vector components. Part (a) requires calculating change in momentum using vector subtraction and finding magnitude—standard M2 technique. Part (b) involves finding an angle between two vectors using dot product or component methods. While it requires careful vector manipulation, it's a routine textbook exercise with no novel problem-solving required, making it slightly easier than average. |
| Spec | 1.10c Magnitude and direction: of vectors6.03f Impulse-momentum: relation6.03g Impulse in 2D: vector form |
A particle $P$ of mass 2 kg is moving with velocity $(3\mathbf{i} + 4\mathbf{j})$ m s$^{-1}$ when it receives an impulse. Immediately after the impulse is applied, $P$ has velocity $(2\mathbf{i} - 3\mathbf{j})$ m s$^{-1}$.
\begin{enumerate}[label=(\alph*)]
\item Find the magnitude of the impulse. [5]
\item Find the angle between the direction of the impulse and the direction of motion of $P$ immediately before the impulse is applied. [3]
\end{enumerate}
\hfill \mbox{\textit{Edexcel M2 2014 Q1 [8]}}