| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2011 |
| Session | June |
| Marks | 11 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Vectors Introduction & 2D |
| Type | When is one object due north/east/west/south of another |
| Difficulty | Moderate -0.3 This is a standard M1 kinematics question using vectors with straightforward applications: finding a bearing using arctangent, writing position vectors using r = r₀ + vt, and solving simple equations when components satisfy directional conditions. All techniques are routine for M1 with no novel problem-solving required, making it slightly easier than average. |
| Spec | 1.10c Magnitude and direction: of vectors1.10d Vector operations: addition and scalar multiplication1.10h Vectors in kinematics: uniform acceleration in vector form |
| Answer | Marks | Guidance |
|---|---|---|
| \(\tan\theta = \frac{3}{4}\); bearing is \(37°\) | M1; A1 | nearest degree |
| (2) |
| Answer | Marks |
|---|---|
| \(\mathbf{p} = (\mathbf{i} + \mathbf{j}) + t(2\mathbf{i} - 3\mathbf{j})\) | M1 A1 |
| Answer | Marks |
|---|---|
| \(\mathbf{q} = (-2\mathbf{j}) + t(3\mathbf{i} + 4\mathbf{j})\) | A1 |
| Answer | Marks |
|---|---|
| \(\mathbf{PQ} = \mathbf{q} - \mathbf{p} = (-\mathbf{i} - 3\mathbf{j}) + t(\mathbf{i} + 7\mathbf{j})\) | M1 A1 |
| (5) |
| Answer | Marks |
|---|---|
| \(-1 + t = 0\) | M1 |
| \(t = 1\) or \(3\text{pm}\) | A1 |
| Answer | Marks |
|---|---|
| \(-1 + t = -(-3 + 7t)\) | M1 |
| \(t = \frac{1}{3}\) or \(2.30 \text{ pm}\) | A1 |
| (4) | |
| 11 |
## (a)
$\tan\theta = \frac{3}{4}$; bearing is $37°$ | M1; A1 | **nearest degree**
| (2) |
## (b)
### (i)
$\mathbf{p} = (\mathbf{i} + \mathbf{j}) + t(2\mathbf{i} - 3\mathbf{j})$ | M1 A1 |
### (ii)
$\mathbf{q} = (-2\mathbf{j}) + t(3\mathbf{i} + 4\mathbf{j})$ | A1 |
### (iii)
$\mathbf{PQ} = \mathbf{q} - \mathbf{p} = (-\mathbf{i} - 3\mathbf{j}) + t(\mathbf{i} + 7\mathbf{j})$ | M1 A1 |
| (5) |
## (c)
### (i)
$-1 + t = 0$ | M1 |
$t = 1$ or $3\text{pm}$ | A1 |
### (ii)
$-1 + t = -(-3 + 7t)$ | M1 |
$t = \frac{1}{3}$ or $2.30 \text{ pm}$ | A1 |
| (4) |
| **11** |
[In this question $\mathbf{i}$ and $\mathbf{j}$ are unit vectors due east and due north respectively. Position vectors are given relative to a fixed origin $O$.]
Two ships $P$ and $Q$ are moving with constant velocities. Ship $P$ moves with velocity $(2\mathbf{i} - 3\mathbf{j})$ km h$^{-1}$ and ship $Q$ moves with velocity $(3\mathbf{i} + 4\mathbf{j})$ km h$^{-1}$.
\begin{enumerate}[label=(\alph*)]
\item Find, to the nearest degree, the bearing on which $Q$ is moving. [2]
\end{enumerate}
At 2 pm, ship $P$ is at the point with position vector $(\mathbf{i} + \mathbf{j})$ km and ship $Q$ is at the point with position vector $(-2\mathbf{j})$ km.
At time $t$ hours after 2 pm, the position vector of $P$ is $\mathbf{p}$ km and the position vector of $Q$ is $\mathbf{q}$ km.
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Write down expressions, in terms of $t$, for
\begin{enumerate}[label=(\roman*)]
\item $\mathbf{p}$,
\item $\mathbf{q}$,
\item $\overrightarrow{PQ}$. [5]
\end{enumerate}
\item Find the time when
\begin{enumerate}[label=(\roman*)]
\item $Q$ is due north of $P$,
\item $Q$ is north-west of $P$. [4]
\end{enumerate}
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2011 Q7 [11]}}