| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2013 |
| Session | January |
| Marks | 16 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Pulley systems |
| Type | Particle on rough incline, particle hanging |
| Difficulty | Standard +0.8 This is a substantial multi-stage pulley problem requiring force resolution on an incline with friction, connected particle equations, energy considerations after impact, and tracking motion through two phases. While the techniques are standard M1 content (resolving forces, F=ma, friction), the problem requires careful bookkeeping across multiple stages and the final part demands insight into energy methods or SUVAT across discontinuous motion, making it moderately challenging for M1 level. |
| Spec | 3.03e Resolve forces: two dimensions3.03k Connected particles: pulleys and equilibrium3.03o Advanced connected particles: and pulleys3.03v Motion on rough surface: including inclined planes6.02i Conservation of energy: mechanical energy principle |
| Answer | Marks | Guidance |
|---|---|---|
| Inextensible string | B1 | (1) |
| Answer | Marks | Guidance |
|---|---|---|
| \(4mg - T = 4ma\) | M1 A1 | |
| \(T - 2mg \sin \alpha - F = 2ma\) | M1 A1 | (4) |
| Answer | Marks | Guidance |
|---|---|---|
| \(F = 0.25R\) | B1 | |
| \(R = 2mg \cos \alpha\) | B1 | |
| \(\cos \alpha = 0.8\) or \(\sin \alpha = 0.6\) | B1 | |
| Eliminating \(R, F\) and \(T\) | M1 | |
| \(a = 0.4g = 3.92\) | A1 | (5) |
| Answer | Marks | Guidance |
|---|---|---|
| \(v^2 = 2 \times 0.4g h\) | M1 | |
| \(-2mg \sin \alpha - F = 2ma'\) | M1 | |
| \(a' = -0.8g\) | A1 | |
| \(0^2 = 0.8gh - 2x \times 0.8g \times s\) | M1 | |
| \(s = 0.5h\) | A1 | |
| \(XY = 0.5h + h = 1.5h\) | A1 | (6) |
### Part (a)
Inextensible string | B1 | (1)
### Part (b)
$4mg - T = 4ma$ | M1 A1 |
$T - 2mg \sin \alpha - F = 2ma$ | M1 A1 | (4)
### Part (c)
$F = 0.25R$ | B1 |
$R = 2mg \cos \alpha$ | B1 |
$\cos \alpha = 0.8$ or $\sin \alpha = 0.6$ | B1 |
Eliminating $R, F$ and $T$ | M1 |
$a = 0.4g = 3.92$ | A1 | (5)
### Part (d)
$v^2 = 2 \times 0.4g h$ | M1 |
$-2mg \sin \alpha - F = 2ma'$ | M1 |
$a' = -0.8g$ | A1 |
$0^2 = 0.8gh - 2x \times 0.8g \times s$ | M1 |
$s = 0.5h$ | A1 |
$XY = 0.5h + h = 1.5h$ | A1 | (6)
**Total for Question 7: 16**
\includegraphics{figure_5}
Figure 5 shows two particles $A$ and $B$, of mass $2m$ and $4m$ respectively, connected by a light inextensible string. Initially $A$ is held at rest on a rough inclined plane which is fixed to horizontal ground. The plane is inclined to the horizontal at an angle $\alpha$, where $\tan\alpha = \frac{3}{4}$. The coefficient of friction between $A$ and the plane is $\frac{1}{4}$. The string passes over a small smooth pulley $P$ which is fixed at the top of the plane. The part of the string from $A$ to $P$ is parallel to a line of greatest slope of the plane and $B$ hangs vertically below $P$. The system is released from rest with the string taut, with $A$ at the point $X$ and with $B$ at a height $h$ above the ground.
For the motion until $B$ hits the ground,
\begin{enumerate}[label=(\alph*)]
\item give a reason why the magnitudes of the accelerations of the two particles are the same, [1]
\item write down an equation of motion for each particle, [4]
\item find the acceleration of each particle. [5]
\end{enumerate}
Particle $B$ does not rebound when it hits the ground and $A$ continues moving up the plane towards $P$. Given that $A$ comes to rest at the point $Y$, without reaching $P$,
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{3}
\item find the distance $XY$ in terms of $h$. [6]
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2013 Q7 [16]}}