Edexcel C3 — Question 13 10 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Marks10
PaperDownload PDF ↗
TopicDifferentiating Transcendental Functions
TypeFind tangent line equation
DifficultyModerate -0.3 This is a straightforward C3 differentiation question requiring standard techniques: differentiating ln(3x) and e^x, finding a tangent equation, and locating a y-intercept. Part (a) is routine substitution to verify an inequality. The algebraic manipulation is minimal and all steps follow textbook procedures with no novel insight required. Slightly easier than average due to its predictable structure.
Spec1.07j Differentiate exponentials: e^(kx) and a^(kx)1.07l Derivative of ln(x): and related functions1.07m Tangents and normals: gradient and equations1.09a Sign change methods: locate roots

\includegraphics{figure_1} Figure 1 shows a sketch of the curve with equation \(y = f(x)\), where $$f(x) = 10 + \ln(3x) - \frac{1}{2}e^x, \quad 0.1 \leq x \leq 3.3.$$ Given that \(f(k) = 0\),
  1. show, by calculation, that \(3.1 < k < 3.2\). [2]
  2. Find \(f'(x)\). [3]
The tangent to the graph at \(x = 1\) intersects the \(y\)-axis at the point \(P\).
    1. Find an equation of this tangent.
    2. Find the exact \(y\)-coordinate of \(P\), giving your answer in the form \(a + \ln b\). [5]

\includegraphics{figure_1}

Figure 1 shows a sketch of the curve with equation $y = f(x)$, where
$$f(x) = 10 + \ln(3x) - \frac{1}{2}e^x, \quad 0.1 \leq x \leq 3.3.$$
Given that $f(k) = 0$,

\begin{enumerate}[label=(\alph*)]
\item show, by calculation, that $3.1 < k < 3.2$. [2]
\item Find $f'(x)$. [3]
\end{enumerate}

The tangent to the graph at $x = 1$ intersects the $y$-axis at the point $P$.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item 
\begin{enumerate}[label=(\roman*)]
\item Find an equation of this tangent.
\item Find the exact $y$-coordinate of $P$, giving your answer in the form $a + \ln b$. [5]
\end{enumerate}
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3  Q13 [10]}}