Edexcel C2 — Question 10 11 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Marks11
PaperDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeSum/difference of two binomials simplification
DifficultyStandard +0.3 This is a straightforward binomial expansion question requiring students to expand two binomials, observe that odd powers cancel, collect coefficients, then solve a quadratic equation. While it involves multiple steps and a substitution, the techniques are standard C2 material with no novel insight required—slightly easier than average due to the symmetric structure that simplifies the algebra.
Spec1.02f Solve quadratic equations: including in a function of unknown1.04a Binomial expansion: (a+b)^n for positive integer n

  1. Given that $$(2 + x)^5 + (2 - x)^5 = A + Bx^2 + Cx^4,$$ find the values of the constants \(A\), \(B\) and \(C\). [6]
  2. Using the substitution \(y = x^2\) and your answers to part (a), solve, $$(2 + x)^5 + (2 - x)^5 = 349.$$ [5]

\begin{enumerate}[label=(\alph*)]
\item Given that
$$(2 + x)^5 + (2 - x)^5 = A + Bx^2 + Cx^4,$$
find the values of the constants $A$, $B$ and $C$. [6]

\item Using the substitution $y = x^2$ and your answers to part (a), solve,
$$(2 + x)^5 + (2 - x)^5 = 349.$$ [5]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C2  Q10 [11]}}