CAIE S2 2016 June — Question 6 9 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2016
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPoisson distribution
TypeSample mean distribution of Poisson
DifficultyStandard +0.3 This is a straightforward application of standard Poisson distribution properties (sum of independent Poissons, sampling distribution of means) with routine calculations. Part (i) uses Po(3.9) for the sum, parts (ii)-(iii) apply CLT/normal approximation with given formulas. No novel insight required, just methodical application of learned techniques.
Spec5.02n Sum of Poisson variables: is Poisson5.04b Linear combinations: of normal distributions5.05a Sample mean distribution: central limit theorem

\(X\) and \(Y\) are independent random variables with distributions \(\mathrm{Po}(1.6)\) and \(\mathrm{Po}(2.3)\) respectively.
  1. Find \(\mathrm{P}(X + Y = 4)\). [3]
A random sample of 75 values of \(X\) is taken.
  1. State the approximate distribution of the sample mean, \(\overline{X}\), including the values of the parameters. [2]
  2. Hence find the probability that the sample mean is more than 1.7. [3]
  3. Explain whether the Central Limit theorem was needed to answer part (ii). [1]

$X$ and $Y$ are independent random variables with distributions $\mathrm{Po}(1.6)$ and $\mathrm{Po}(2.3)$ respectively.

\begin{enumerate}[label=(\roman*)]
\item Find $\mathrm{P}(X + Y = 4)$. [3]
\end{enumerate}

A random sample of 75 values of $X$ is taken.

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item State the approximate distribution of the sample mean, $\overline{X}$, including the values of the parameters. [2]

\item Hence find the probability that the sample mean is more than 1.7. [3]

\item Explain whether the Central Limit theorem was needed to answer part (ii). [1]
\end{enumerate}

\hfill \mbox{\textit{CAIE S2 2016 Q6 [9]}}