| Exam Board | CAIE |
|---|---|
| Module | S2 (Statistics 2) |
| Year | 2024 |
| Session | November |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Continuous Probability Distributions and Random Variables |
| Type | Piecewise PDF with k |
| Difficulty | Moderate -0.3 This is a standard two-part PDF question requiring routine integration techniques. Part (a) uses the fundamental property that the PDF integrates to 1, and part (b) applies the definition of expectation. Both involve straightforward polynomial integration with no conceptual challenges or novel problem-solving, making it slightly easier than average for A-level statistics. |
| Spec | 5.03a Continuous random variables: pdf and cdf5.03c Calculate mean/variance: by integration |
| Answer | Marks |
|---|---|
| 4(a) | 3 |
| Answer | Marks | Guidance |
|---|---|---|
| 2 | M1 | Attempt integrate f(x), ignore limits and ‘= 1’. |
| Answer | Marks | Guidance |
|---|---|---|
| x x2 2 | A1 | OE Correct integration and limits. |
| Answer | Marks | Guidance |
|---|---|---|
| 3 2 4 2 | A1 | Must see correct substitution of limits. |
| Answer | Marks | Guidance |
|---|---|---|
| Question | Answer | Marks |
| Answer | Marks |
|---|---|
| 4(b) | 3 |
| Answer | Marks | Guidance |
|---|---|---|
| 2 | M1 | Attempt to integrate xf(x), ignore limits. |
| Answer | Marks | Guidance |
|---|---|---|
| 2 x 2 2 x 2 | A1 | Correct integration and limits. |
| Answer | Marks | Guidance |
|---|---|---|
| 2 2 2 2 | A1 | Must see correct substitution of limits. |
| Answer | Marks | Guidance |
|---|---|---|
| Question | Answer | Marks |
Question 4:
--- 4(a) ---
4(a) | 3
(a −18)dx = 1
x2 x3
2 | M1 | Attempt integrate f(x), ignore limits and ‘= 1’.
3
−a + 9 = 1
x x2 2 | A1 | OE Correct integration and limits.
−a +1+a −9 = 1 a = 2 7 (AG)
3 2 4 2 | A1 | Must see correct substitution of limits.
Correct working no errors seen.
3
Question | Answer | Marks | Guidance
--- 4(b) ---
4(b) | 3
(27 −18)dx
2x x2
2 | M1 | Attempt to integrate xf(x), ignore limits.
3 3
27lnx+18 or 27ln2x+18
2 x 2 2 x 2 | A1 | Correct integration and limits.
OE e.g. using ln 2x.
= 27ln3+ 6 − 27ln2 − 9 = 27ln3 − 3 AG
2 2 2 2 | A1 | Must see correct substitution of limits.
Correct working no errors seen.
3
Question | Answer | Marks | Guidance
A random variable $X$ has probability density function $f$ defined by
$$f(x) = \begin{cases}
\frac{a}{x^2} - \frac{18}{x^3} & 2 \leqslant x < 3, \\
0 & \text{otherwise},
\end{cases}$$
where $a$ is a constant.
\begin{enumerate}[label=(\alph*)]
\item Show that $a = \frac{27}{2}$. [3]
\item Show that $\text{E}(X) = \frac{27}{2} \ln \frac{3}{2} - 3$. [3]
\end{enumerate}
\hfill \mbox{\textit{CAIE S2 2024 Q4 [6]}}