CAIE S2 2023 November — Question 3 10 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2023
SessionNovember
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPoisson distribution
TypeSingle period normal approximation - scaled period (exact Poisson part)
DifficultyStandard +0.3 This is a straightforward Poisson distribution question requiring standard techniques: scaling the parameter for different time periods, using tables/calculator for probabilities, applying normal approximation with continuity correction, and recognizing that constant rate is a Poisson assumption. All parts are routine applications with no novel problem-solving required, making it slightly easier than average.
Spec5.02i Poisson distribution: random events model5.02j Poisson formula: P(X=x) = e^(-lambda)*lambda^x/x!5.02k Calculate Poisson probabilities

A website owner finds that, on average, his website receives 0.3 hits per minute. He believes that the number of hits per minute follows a Poisson distribution.
  1. Assume that the owner is correct.
    1. Find the probability that there will be at least 4 hits during a 10-minute period. [3]
    2. Use a suitable approximating distribution to find the probability that there will be fewer than 40 hits during a 3-hour period. [4]
A friend agrees that the website receives, on average, 0.3 hits per minute. However, she notices that the number of hits during the day-time (9.00am to 9.00pm) is usually about twice the number of hits during the night-time (9.00pm to 9.00am).
    1. Explain why this fact contradicts the owner's belief that the number of hits per minute follows a Poisson distribution. [1]
    2. Specify separate Poisson distributions that might be suitable models for the number of hits during the day-time and during the night-time. [2]

Question 3:

AnswerMarks Guidance
3(a)(i)λ = 3 B1
1 – e–3(1 + 3 + 32 + 33 ) or 1 – e–3(1 + 3 + 4.5 + 4.5)
2 3!
AnswerMarks Guidance
or 1 – (0.04979 + 0.14936 + 0.22404 + 0.22404)M1 Any λ. Allow one end error.
= 0.353 (3 sf)A1 No working scores B1.
3

AnswerMarks Guidance
3(a)(ii)N(54, 54) M1
39.5−54
(= –1.973)
AnswerMarks Guidance
54M1 Allow with wrong or no continuity correction.
For standardising with their mean and variance.
AnswerMarks Guidance
1 – ɸ ('1.973')M1 For area consistent with their working.
= 0.0242 (3 sf)A1 Special case: if no working seen, 0.0242 scores SC B3,
0.0284 scores SC B2.
4

AnswerMarks
3(b)(i)‘Mean not constant’ or’ ‘number of hits per minute not constant’ or ‘not a
constant rate’B1
1

AnswerMarks Guidance
3(b)(ii)2p + p = 2 × 0.3 [p = 0.2]
[where p is the rate per minute for night time]M1 May be implied by answer.
[During day-time]: Po(0.4). [During night-time]: Po(0.2)A1 Accept Po(24) [per daytime hour], Po(12) [per night
time hour].
Accept Po(288) [per day time shift], Po(144)[ per night
time shift].
Note: Po(432), Po(216) scores M0A0.
2
AnswerMarks Guidance
QuestionAnswer Marks
Question 3:
--- 3(a)(i) ---
3(a)(i) | λ = 3 | B1 | For mean = 3.
1 – e–3(1 + 3 + 32 + 33 ) or 1 – e–3(1 + 3 + 4.5 + 4.5)
2 3!
or 1 – (0.04979 + 0.14936 + 0.22404 + 0.22404) | M1 | Any λ. Allow one end error.
= 0.353 (3 sf) | A1 | No working scores B1.
3
--- 3(a)(ii) ---
3(a)(ii) | N(54, 54) | M1 | soi
39.5−54
(= –1.973)
54 | M1 | Allow with wrong or no continuity correction.
For standardising with their mean and variance.
1 – ɸ ('1.973') | M1 | For area consistent with their working.
= 0.0242 (3 sf) | A1 | Special case: if no working seen, 0.0242 scores SC B3,
0.0284 scores SC B2.
4
--- 3(b)(i) ---
3(b)(i) | ‘Mean not constant’ or’ ‘number of hits per minute not constant’ or ‘not a
constant rate’ | B1
1
--- 3(b)(ii) ---
3(b)(ii) | 2p + p = 2 × 0.3 [p = 0.2]
[where p is the rate per minute for night time] | M1 | May be implied by answer.
[During day-time]: Po(0.4). [During night-time]: Po(0.2) | A1 | Accept Po(24) [per daytime hour], Po(12) [per night
time hour].
Accept Po(288) [per day time shift], Po(144)[ per night
time shift].
Note: Po(432), Po(216) scores M0A0.
2
Question | Answer | Marks | Guidance
A website owner finds that, on average, his website receives 0.3 hits per minute. He believes that the number of hits per minute follows a Poisson distribution.

\begin{enumerate}[label=(\alph*)]
\item Assume that the owner is correct.
\begin{enumerate}[label=(\roman*)]
\item Find the probability that there will be at least 4 hits during a 10-minute period. [3]

\item Use a suitable approximating distribution to find the probability that there will be fewer than 40 hits during a 3-hour period. [4]
\end{enumerate}
\end{enumerate}

A friend agrees that the website receives, on average, 0.3 hits per minute. However, she notices that the number of hits during the day-time (9.00am to 9.00pm) is usually about twice the number of hits during the night-time (9.00pm to 9.00am).

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item 
\begin{enumerate}[label=(\roman*)]
\item Explain why this fact contradicts the owner's belief that the number of hits per minute follows a Poisson distribution. [1]

\item Specify separate Poisson distributions that might be suitable models for the number of hits during the day-time and during the night-time. [2]
\end{enumerate}
\end{enumerate}

\hfill \mbox{\textit{CAIE S2 2023 Q3 [10]}}