CAIE S1 2014 November — Question 3 7 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2014
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Distribution
TypeIndependent binomial samples with compound probability
DifficultyStandard +0.3 Part (i) requires systematic enumeration of ways four dice sum to 5 (only 1+1+1+2 and permutations), which is straightforward but requires care. Part (ii) is a standard binomial probability application using the result from (i). Both parts involve routine techniques with no novel insight, making this slightly easier than average for A-level.
Spec2.04a Discrete probability distributions2.04b Binomial distribution: as model B(n,p)2.04c Calculate binomial probabilities5.01a Permutations and combinations: evaluate probabilities

  1. Four fair six-sided dice, each with faces marked 1, 2, 3, 4, 5, 6, are thrown. Find the probability that the numbers shown on the four dice add up to 5. [3]
  2. Four fair six-sided dice, each with faces marked 1, 2, 3, 4, 5, 6, are thrown on 7 occasions. Find the probability that the numbers shown on the four dice add up to 5 on exactly 1 or 2 of the 7 occasions. [4]

(i) One of \(1 \mid 1 \mid 2\), or \(1 \mid 2 \mid 1\), or \(2 \mid 1 \mid 1\), or \(2 \mid 1 \mid 1\)
AnswerMarks Guidance
\[\text{Prob} = \frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{324} (0.00309)\]M1, M1, A1 3 One of \(1 \mid 1 \mid 2\) seen or Mult a prob by 4 or \((\frac{1}{6})^4 \times\) integer \(k \geq 1\) seen or Correct answer
(ii) \[P(1,2) = ^7C_1 \times (1/324)(323/324)^6 + ^7C_4(1/324)^4(323/324)^3 = 0.0214\]M1, M1, M1, A1 4 Bin term \(^7C_p(q)^{-x} \cdot {}^xC_r\), \(0.99 \leq p + q \leq 1\) or Using their \(p\) from (i) in a bin term or Correct unsimplified answer or Correct answer
**(i)** One of $1 \mid 1 \mid 2$, or $1 \mid 2 \mid 1$, or $2 \mid 1 \mid 1$, or $2 \mid 1 \mid 1$

$$\text{Prob} = \frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{324} (0.00309)$$ | M1, M1, A1 3 | One of $1 \mid 1 \mid 2$ seen or Mult a prob by 4 or $(\frac{1}{6})^4 \times$ integer $k \geq 1$ seen or Correct answer

**(ii)** $$P(1,2) = ^7C_1 \times (1/324)(323/324)^6 + ^7C_4(1/324)^4(323/324)^3 = 0.0214$$ | M1, M1, M1, A1 4 | Bin term $^7C_p(q)^{-x} \cdot {}^xC_r$, $0.99 \leq p + q \leq 1$ or Using their $p$ from (i) in a bin term or Correct unsimplified answer or Correct answer

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\begin{enumerate}[label=(\roman*)]
\item Four fair six-sided dice, each with faces marked 1, 2, 3, 4, 5, 6, are thrown. Find the probability that the numbers shown on the four dice add up to 5. [3]
\item Four fair six-sided dice, each with faces marked 1, 2, 3, 4, 5, 6, are thrown on 7 occasions. Find the probability that the numbers shown on the four dice add up to 5 on exactly 1 or 2 of the 7 occasions. [4]
\end{enumerate}

\hfill \mbox{\textit{CAIE S1 2014 Q3 [7]}}